英文:
Regular expression to disallow empty string and comma
问题
我正在尝试编写一个正则表达式，以限制字符串中的空字符串和逗号。
示例：
string = "" # 不允许
s = "ab c!@#)(*&^%$#~" # 允许
s = "sfsfsf,sdfsdf" # 不允许
这个正则表达式的目的是在Swagger文档中进行模式匹配，就像这个属性一样：type: string pattern: "^[0-9A-Za-z_]+$" value: type: object
我尝试了这个正则表达式 ^(?!\s*$)[^,]*$，但它在Swagger文档中不受支持，并且我在golang代码中使用这个正则表达式时出现了以下错误：
invalid or unsupported Perl syntax: `(?!
英文:
I'm trying to write regular expression to restrict empty string and comma inside a string
example:
string = "" # not allowed
s = "ab c!@#)(*&^%$#~" # allowed
s = "sfsfsf,sdfsdf" # not allowed
The intention of this regexp is to do a pattern matching in swagger documentation like this property: type: string pattern: "^[0-9A-Za-z_]+$" value: type: object
I tried this regular expression ^(?!\s*$)[^,]*$ but it is not supported inside swagger doc and I get this error in golang code for this regular expression:
> invalid or unsupported Perl syntax: `(?!
答案1
得分: 3
实际上，你不需要前瞻。
只需删除前瞻表达式，并将 * 更改为 +，这将要求至少一个字符，并简化你的正则表达式为 ^[^,]+$
如果这样可以解决问题，或者如果你有更多条件，请告诉我。
编辑：
考虑到 @JvdV 的评论（他似乎是对的），你可以使用以下正则表达式：
^\s*([^,\s]+\s*)+$
如果至少有一个非空白字符，这将匹配，并且如果有一个逗号的出现，整个字符串将被拒绝
编辑1：
为了避免灾难性回溯，可以将正则表达式简化如下：
^\s*[^,\s][^,]*$
解释：
^- 匹配输入的开头\s*- 可选地匹配任何空白字符[^,\s]- 匹配至少一个逗号和空白字符之外的字符[^,]*- 可以跟随任何逗号之外的字符，零次或多次$- 匹配字符串的结尾
编辑2：为了避免前导/尾随空白字符，你可以使用以下正则表达式：
^[^\s,]([^,]*[^\s,])?$
英文:
You actually don't need a look ahead.
Just remove that lookahead expression and change * to + which will require at least one character and simplify your regex to ^[^,]+$
Let me know if that works or if you have more conditions.
Edit:
Considering @JvdV's comment (and he seems right), you can use following regex,
^\s*([^,\s]+\s*)+$
This will match if there is at least one non whitespace character and whole string will be rejected if there is even a single occurrence of a comma
Edit1:
To avoid catastrophic backtracking, the regex can be simplified as following,
^\s*[^,\s][^,]*$
Explanation:
^- Match start of input\s*- Optionally match any whitespaces[^,\s]- Match at least one character other than comma and whitespace[^,]*- Can be followed by any character other than comma zero or more times$- Match end of string
Edit2: For avoiding leading/trailing whitespaces, you can use this regex,
^[^\s,]([^,]*[^\s,])?$
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