英文:
regex golang last match of a pattern inside curly braces
问题
我有以下字符串，我想匹配最后一个大括号（包括括号内的内容），即输出应为{ahhh}。
abc {popo}/popo/{ahhh}
Golang不支持负向先行断言，我尝试了以下模式但没有成功：
{.+?}$
{.+?}([^/])
非常感谢您的帮助。谢谢。
英文:
I have the following string, and I want to match the contents of the last curly brace (inclusive), i.e. the output should be {ahhh}.
abc {popo}/popo/{ahhh}
Golang does not support negative lookahead, and I have tried the following patterns but it has not worked
{.+?}$
{.+?}([^/])
Any help would be much appreciated. Thank you.
答案1
得分: 2
你可以匹配从开头到字符串末尾的闭合大括号：
\{[^{}]*}$
或者你可以匹配整行，并捕获最后一个大括号后面的任意字符（除了斜杠）直到字符串末尾。
.*(\{[^{}]*})[^/]*$
英文:
You could match from an opening till closing curly at the end of the string:
\{[^{}]*}$
Or you could match the whole line, and then capture the last occurrence of the curly's followed by matching any char except / till the end of the string.
.*(\{[^{}]*})[^/]*$
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