将API的JSON响应封装在Go中。

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英文:

Wrap API Json response in Go

问题

很抱歉,我只能提供中文翻译,无法执行代码。以下是您要翻译的内容:

对不起,如果这是一个愚蠢的问题,因为我在Go语言方面非常新手。
根据业务逻辑,我调用了几个API,返回不同类型的响应,如JSON数组、嵌套JSON和单个JSON对象。
我需要将根据业务逻辑调用的API响应包装成一个通用格式,如下所示:

{
"data": "这里是API响应",
"statusCode": 200
}

我尝试了一些方法,但输出不符合预期。

type Model[T any] struct {
    Data       T
    StatusCode int
}

model := Model[string]{Data: apiResponse, StatusCode: 200}
out, err := json.Marshal(model)

这段代码的输出是:

{
    "Data": "[{\"name\":\"Harry Potter\",\"city\":\"London\"},{\"name\":\"Don Quixote\",\"city\":\"Madrid\"},{\"name\":\"Joan of Arc\",\"city\":\"Paris\"},{\"name\":\"Rosa Park\",\"city\":\"Alabama\"}]",
    "StatusCode": 200
}

我进行了以下更改:

var result []map[string]interface{} 
json.Unmarshal([]byte(body), &result) 
out, err := json.Marshal(result)

输出结果符合预期,当使用[]map[string]interface{}时,上述API响应是正确的JSON格式。
问题是,只有返回JSON数组的API才适用于此方法。对于返回单个JSON对象的API,为了使其正常工作,我需要进行以下更改:

map[string]interface`

即移除数组映射。
我希望能够使其通用化,以便任何类型的JSON响应都可以映射到其中。

英文:

I am sorry if this is a silly question because i am very new in Go.
I am calling couple of apis on the base of business logic, different types of response coming like json array, nest json and single json object.
i need to wrap a api response that called according to business logic in a common format like:

{
"data":"api response here",
"statusCode":200
}

i tried some but its not expect output

type Model[T any] struct {
    Data       T
    StatusCode int
}

model := Model[string]{Data: apiResponse, StatusCode: 200}
out, err := json.Marshal(model)

out put of this code is

{
    "Data": "[{\"name\":\"Harry Potter\",\"city\":\"London\"},{\"name\":\"Don Quixote\",\"city\":\"Madrid\"},{\"name\":\"Joan of Arc\",\"city\":\"Paris\"},{\"name\":\"Rosa Park\",\"city\":\"Alabama\"}]",
    "StatusCode": 200
}

this i made these changes

var result []map[string]interface{} 
json.Unmarshal([]byte(body), &result) 
out, err := json.Marshal(result)

output was as expected, above api response was in proper json when use []map[string]interface
problem is, its only for those api that return array of json. those apis returning single json object then to make it work i need to do this

map[string]interface`

means remove the array map.
i need to make it generic so that any kind of json response map into it.

答案1

得分: 1

使用interface{}类型的Data字段

type APIResponse struct {
	Data       interface{} `json:"data"`
	StatusCode int         `json:"statusCode"`
}

然后你可以将任何API响应类型分配给Data字段并进行编组。

func main() {
	r := []Person{
		{
			Name: "Harry Porter",
			City: "London",
		},
		{
			Name: "Don Quixote",
			City: "Madrid",
		},
	}

	res := APIResponse{
		Data:       r,
		StatusCode: 200,
	}

	resByt, err := json.Marshal(res)
	if err != nil {
		panic(err)
	}

	fmt.Println(string(resByt))
}

输出结果

{"data":[{"name":"Harry Porter","city":"London"},{"name":"Don Quixote","city":"Madrid"}],"statusCode":200}

Playground中运行完整代码。

英文:

Use type of field Data as an interface{}

type APIResponse struct {
	Data       interface{} `json:"data"`
	StatusCode int         `json:"statusCode"`
}

And then you can assign any API Response type to the Data field and marshal it.

func main() {
	r := []Person{
		{
			Name: "Harry Porter",
			City: "London",
		},
		{
			Name: "Don Quixote",
			City: "Madrid",
		},
	}

	res := APIResponse{
		Data:       r,
		StatusCode: 200,
	}

	resByt, err := json.Marshal(res)
	if err != nil {
		panic(err)
	}

	fmt.Println(string(resByt))
}

Output

{"data":[{"name":"Harry Porter","city":"London"},{"name":"Don Quixote","city":"Madrid"}],"statusCode":200}

Run the full code here in Playground.

答案2

得分: 0

你可以简单地这样做:

result := map[string]interface{}{
   "data":       apiResponse,
   "statusCode": 200,
}
out, err := json.Marshal(result)
英文:

You can simply do:

result:=map[string]interface{} {
   "data": apiResponse,
   "statusCode": 200,
}
out, err:=json.Marshal(result)

huangapple
  • 本文由 发表于 2022年8月11日 05:17:30
  • 转载请务必保留本文链接:https://go.coder-hub.com/73312823.html
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