如何使用Go获取XML中指定的结构？

huangapple
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英文:

How to get structure specified in XML with Go?

问题

我有一个名为test.xml的XML文件，内容如下：

  1. <metalib tagsetversion="1" name="TLog" version="1">
  2.   <struct name="STRUCT_1">
  3.     <entry name="ENTRY_1"/>
  4.   </struct>
  6.   <struct name="STRUCT_2">
  7.     <entry name="ENTRY_1"/>
  8.     <entry name="ENTRY_2"/>
  9.   </struct>
  11.    <!-- 其他结构体 -->
  13.   <union name="UNION" version="1">
  14.     <entry type="STRUCT_1"       id="ID_STRUCT_1" />
  15.     <entry type="STRUCT_2"       id="ID_STRUCT_2" />
  16.   </union>
  17. </metalib>

我想要将其解析为以下结构体：

map["STRUCT_1"] == ["ENTRY_1"]，map["STRUCT_2"] == ["ENTRY_1","ENTRY_2"]

还有另一个映射：

map2["ID_STRUCT_1"] == "STRUCT_1"，map2["ID_STRUCT_2"] == "STRUCT_2"

我尝试使用github.com/clbanning/mxj/x2j来解决这个问题，我的代码如下：

  1. package main
  3. import (
  4. 	"encoding/json"
  5. 	"os"
  6. 	"fmt"
  7. 	"testing"
  9. 	"github.com/clbanning/mxj/x2j"
  10. )
  12. func TestXml2Map(t *testing.T) {
  13. 	filePath := "test.xml"
  14. 	fi, fierr := os.Stat(filePath)
  15. 	if fierr != nil {
  16. 		fmt.Println("fierr:", fierr.Error())
  17. 		return
  18. 	}
  19. 	fh, fherr := os.Open(filePath)
  20. 	if fherr != nil {
  21. 		fmt.Println("fherr:", fherr.Error())
  22. 		return
  23. 	}
  24. 	defer fh.Close()
  25. 	buf := make([]byte, fi.Size())
  26. 	_, nerr := fh.Read(buf)
  27. 	if nerr != nil {
  28. 		fmt.Println("nerr:", nerr.Error())
  29. 		return
  30. 	}
  31. 	mmap, merr := x2j.XmlToMap(buf)
  32. 	if merr != nil {
  33. 		fmt.Println("merr:", merr.Error())
  34. 		return
  35. 	}
  36. 	// fmt.Println("mmap:", mmap)
  37. 	metalib := mmap["metalib"]
  38. 	// fmt.Println("metalib:", metalib)
  40. 	json.Unmarshal(buf, &metalib)
  41. 	mapmetalib := metalib.(map[string]interface{})
  42. 	// fmt.Println("mapmetalib struct: ", mapmetalib["struct"])
  44. 	istruct := mapmetalib["struct"]
  45. 	json.Unmarshal(buf, &istruct)
  46. 	mapstruct := istruct.([]interface{})
  47. 	fmt.Println("mapstruct: ", mapstruct)
  48. }

但我感到困惑，不知道下一步该怎么做。

英文:

I have an XML file like this test.xml

  1. &lt;metalib tagsetversion=&quot;1&quot; name=&quot;TLog&quot; version=&quot;1&quot;&gt;
  2.   &lt;struct name=&quot;STRUCT_1&quot;&gt;
  3.     &lt;entry name=&quot;ENTRY_1&quot;/&gt;
  4.   &lt;/struct&gt;
  6.   &lt;struct name=&quot;STRUCT_2&quot;&gt;
  7.     &lt;entry name=&quot;ENTRY_1&quot;/&gt;
  8.     &lt;entry name=&quot;ENTRY_2&quot;/&gt;
  9.   &lt;/struct&gt;
  11.    &lt;!-- many structs --&gt;
  13.   &lt;union name=&quot;UNION&quot; version=&quot;1&quot;&gt;
  14.     &lt;entry type=&quot;STRUCT_1&quot;       id=&quot;ID_STRUCT_1&quot; /&gt;
  15.     &lt;entry type=&quot;STRUCT_2&quot;       id=&quot;ID_STRUCT_2&quot; /&gt;
  16.   &lt;/union&gt;
  17. &lt;/metalib&gt;

And I want parse it to go struct like this:

map[&quot;STRUCT_1&quot;] == [&quot;ENTRY_1&quot;], map[&quot;STRUCT_2&quot;] == [&quot;ENTRY_1&quot;,&quot;ENTRY_2&quot;]

and another map:

map2[&quot;ID_STRUCT_1&quot;] == &quot;STRUCT_1&quot;, map2[&quot;ID_STRUCT_2&quot;] == &quot;STRUCT_2&quot;

I have tried to use github.com/clbanning/mxj/x2j slove this problem, and my code like this:

  1. package main
  3. import (
  4. 	&quot;encoding/json&quot;
  5. 	&quot;os&quot;
  6. 	&quot;fmt&quot;
  7. 	&quot;testing&quot;
  9. 	&quot;github.com/clbanning/mxj/x2j&quot;
  10. )
  12. func TestXml2Map(t *testing.T) {
  13. 	filePath := &quot;test.xml&quot;
  14. 	fi, fierr := os.Stat(filePath)
  15. 	if fierr != nil {
  16. 		fmt.Println(&quot;fierr:&quot;, fierr.Error())
  17. 		return
  18. 	}
  19. 	fh, fherr := os.Open(filePath)
  20. 	if fherr != nil {
  21. 		fmt.Println(&quot;fherr:&quot;, fherr.Error())
  22. 		return
  23. 	}
  24. 	defer fh.Close()
  25. 	buf := make([]byte, fi.Size())
  26. 	_, nerr := fh.Read(buf)
  27. 	if nerr != nil {
  28. 		fmt.Println(&quot;nerr:&quot;, nerr.Error())
  29. 		return
  30. 	}
  31. 	mmap, merr := x2j.XmlToMap(buf)
  32. 	if merr != nil {
  33. 		fmt.Println(&quot;merr:&quot;, merr.Error())
  34. 		return
  35. 	}
  36. 	// fmt.Println(&quot;mmap:&quot;, mmap)
  37. 	metalib := mmap[&quot;metalib&quot;]
  38. 	// fmt.Println(&quot;metalib:&quot;, metalib)
  40. 	json.Unmarshal(buf, &amp;metalib)
  41. 	mapmetalib := metalib.(map[string]interface{})
  42. 	// fmt.Println(&quot;mapmetalib struct: &quot;, mapmetalib[&quot;struct&quot;])
  44. 	istruct := mapmetalib[&quot;struct&quot;]
  45. 	json.Unmarshal(buf, &amp;istruct)
  46. 	mapstruct := istruct.([]interface{})
  47. 	fmt.Println(&quot;mapstruct: &quot;, mapstruct)
  48. }

But I am confused and don't know how to do next step.

答案1

得分: 1

  1. package main
  3. import (
  4. 	"encoding/xml"
  5. 	"fmt"
  6. )
  8. type entry struct {
  9. 	Name string `xml:"name,attr"`
  10. }
  11. type Struct struct {
  12. 	Name  string  `xml:"name,attr"`
  13. 	Entry []entry `xml:"entry"`
  14. }
  15. type metalib struct {
  16. 	XMLName xml.Name `xml:"metalib"`
  17. 	Struct  []Struct `xml:"struct"`
  18. }
  20. func main() {
  21. 	datastr := []byte(`<metalib tagsetversion="1" name="TLog" version="1">
  22. 		<struct name="STRUCT_1">
  23. 			<entry name="ENTRY_1"/>
  24. 		</struct>
  26. 		<struct name="STRUCT_2">
  27. 			<entry name="ENTRY_1"/>
  28. 			<entry name="ENTRY_2"/>
  29. 		</struct>
  31. 		<!-- many structs -->
  33. 		<union name="UNION" version="1">
  34. 		<entry type="STRUCT_1"       id="ID_STRUCT_1" />
  35. 		<entry type="STRUCT_2"       id="ID_STRUCT_2" />
  36. 		</union>
  37. 		</metalib>`)
  38. 	metalib := metalib{}
  39. 	err := xml.Unmarshal(datastr, &metalib)
  40. 	if err != nil {
  41. 		return
  42. 	}
  43. 	fmt.Printf("%v\n", metalib)
  45. }
英文: 
  1. package main
  2. import (
  3. &quot;encoding/xml&quot;
  4. &quot;fmt&quot;
  5. )
  6. type entry struct {
  7. Name string `xml:&quot;name,attr&quot;`
  8. }
  9. type Struct struct {
  10. Name  string  `xml:&quot;name,attr&quot;`
  11. Entry []entry `xml:&quot;entry&quot;`
  12. }
  13. type metalib struct {
  14. XMLName xml.Name `xml:&quot;metalib&quot;`
  15. Struct  []Struct `xml:&quot;struct&quot;`
  16. }
  17. func main() {
  18. datastr := []byte(`&lt;metalib tagsetversion=&quot;1&quot; name=&quot;TLog&quot; version=&quot;1&quot;&gt;
  19. &lt;struct name=&quot;STRUCT_1&quot;&gt;
  20. &lt;entry name=&quot;ENTRY_1&quot;/&gt;
  21. &lt;/struct&gt;
  22. &lt;struct name=&quot;STRUCT_2&quot;&gt;
  23. &lt;entry name=&quot;ENTRY_1&quot;/&gt;
  24. &lt;entry name=&quot;ENTRY_2&quot;/&gt;
  25. &lt;/struct&gt;
  26. &lt;!-- many structs --&gt;
  27. &lt;union name=&quot;UNION&quot; version=&quot;1&quot;&gt;
  28. &lt;entry type=&quot;STRUCT_1&quot;       id=&quot;ID_STRUCT_1&quot; /&gt;
  29. &lt;entry type=&quot;STRUCT_2&quot;       id=&quot;ID_STRUCT_2&quot; /&gt;
  30. &lt;/union&gt;
  31. &lt;/metalib&gt;`)
  32. metalib := metalib{}
  33. err := xml.Unmarshal(datastr, &amp;metalib)
  34. if err != nil {
  35. return
  36. }
  37. fmt.Printf(&quot;%v\n&quot;, metalib)
  38. }

huangapple
  • 本文由 发表于 2022年8月9日 19:05:56
  • 转载请务必保留本文链接：https://go.coder-hub.com/73290795.html
  • go
  • json
  • xml
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