英文:
Writing Bytes to strings.builder prints nothing
问题
我正在学习Go语言，对于这段代码为什么没有输出结果感到不确定。
package main
import (
"strings"
)
func main(){
var sb strings.Builder
sb.WriteByte(byte(127))
println(sb.String())
}
我期望它输出 127。
英文:
I am learning go and am unsure why this piece of code prints nothing
package main
import (
"strings"
)
func main(){
var sb strings.Builder
sb.WriteByte(byte(127))
println(sb.String())
}
I would expect it to print 127
答案1
得分: 2
您正在将一个字节追加到字符串的缓冲区中，而不是字符"127"。
由于Go字符串是UTF-8编码的，任何小于等于127的数字都将与ASCII中的相应数字表示相同的字符。您可以在此ASCII表中看到，127代表的是"delete"字符。由于"delete"是一个不可打印的字符，println不会输出任何内容。
这里有一个示例，展示了从您的问题中进行相同操作的示例，但使用了可打印的字符。90代表的是字符"Z"。您可以看到它确实打印出了Z。
如果您想追加字符"127"，您可以使用sb.WriteString("127")或sb.Write([]byte("127"))。如果您想追加字节的字符串表示形式，您可以考虑使用fmt.Sprintf。
注意：我对字符编码不是专家，如果本回答中的术语有误，请谅解。
英文:
You are appending a byte to the string's buffer, not the characters "127".
Since Go strings are UTF-8, any number <=127 will be the same character as that number in ASCII. As you can see in this ASCII chart, 127 will get you the "delete" character. Since "delete" is a non-printable character, println doesn't output anything.
Here's an example of doing the same thing from your question, but using a printable character. 90 for "Z". You can see that it does print out Z.
If you want to append the characters "127" you can use sb.WriteString("127") or sb.Write([]byte("127")). If you want to append the string representation of a byte, you might want to look at using fmt.Sprintf.
Note: I'm not an expert on character encoding so apologies if the terminology in this answer is incorrect.
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