英文:
"panic: strconv.ParseInt: parsing "�": invalid syntax" --> when parting int64 to convert into time
问题
在数据库中，我有一个类型为int64的字段，用于存储Unix时间戳。然后，我想将其作为普通的datetime字符串呈现给用户。然而，这会导致失败。以下是一个简单的示例。
package main
import (
"fmt"
"strconv"
)
func main() {
var a int64
a = 1658545089
tm, err := strconv.ParseInt(string(a), 10, 64)
if err != nil {
panic(err)
}
fmt.Println(tm)
}
===>
panic: strconv.ParseInt: parsing "�": invalid syntax
这里发生了什么？
英文:
In a DB I have a field of type int64 in which I store unix timestamp. Then I want to present it to the user as a normal datetime, as a string. However, it'll fail. Here's a simple example.
package main
import (
"fmt"
"strconv"
)
func main() {
var a int64
a = 1658545089
tm, err := strconv.ParseInt(string(a), 10, 64)
if err != nil {
panic(err)
}
fmt.Println(tm)
}
===>
panic: strconv.ParseInt: parsing "�": invalid syntax
What's going on here?
答案1
得分: -1
这是你要翻译的内容：
这是因为你试图将int64类型转换为字符串。
尝试使用strconv.FormatInt(a, 10)进行转换。
package main
import (
"fmt"
"strconv"
)
func main() {
var a int64
a = 1658545089
tm, err := strconv.ParseInt(strconv.FormatInt(a, 10), 10, 64)
if err != nil {
panic(err)
}
fmt.Println(tm)
}
当你尝试将一个整数转换为字符串时，在Go语言中，它会得到相应的ASCII字符。
https://en.cppreference.com/w/cpp/language/ascii
在某个特定的整数之后，它只会显示�。
英文:
It is because you are trying to convert int64 with string
try it with strconv.FormatInt(a, 10)
package main
import (
"fmt"
"strconv"
)
func main() {
var a int64
a = 1658545089
tm, err := strconv.ParseInt(strconv.FormatInt(a, 10), 10, 64)
if err != nil {
panic(err)
}
fmt.Println(tm)
}
when you try to convert an interger covering with string(), in golang it will get the corresponding ascii character
https://en.cppreference.com/w/cpp/language/ascii
after a certain interger it will only show �
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