可以将可以是字符串或布尔值的 JSON 字段转换为结构体。

huangapple go评论118阅读模式
英文:

Json field that can be string or bool into struct

问题

我正在使用一个API,它返回的字段有时是布尔值,有时是字符串。

像这样:

{
   "unstable": true,
   "unstable_reason": "ANY_REASON"
}

{
   "unstable": false,
   "unstable_reason": false
}

结构看起来像这样:

...
Unstable       bool   `json:"unstable"`
UnstableReason string `json:"unstable_reason,string"`
...

当我尝试使用它时,出现以下错误:

panic: json: invalid use of ,string struct tag, trying to unmarshal unquoted value into string

另一方面,当将UnstableReason的类型设置为bool时,也会出现错误。

当删除,string时,我得到以下错误:
panic: json: cannot unmarshal bool into Go struct field .data.prices.unstable_reason of type string

对于我的目的来说,这个字段并不重要,所以如果有办法让它保持nil,那也可以。

我对API没有影响。

有什么想法吗?我对Go相对较新。

英文:

I am using an API, which returns a field that is sometimes a boolean, sometimes a string.

like this:

{
   "unstable":true,
   "unstable_reason":"ANY_REASON"
}

and

{
   "unstable":false
   "unstable_reason":false
}

the struct looks like this:

        ...
		Unstable       bool   `json:"unstable"`
		UnstableReason string `json:"unstable_reason,string"`
        ...

When trying to use this, I get the following error:

panic: json: invalid use of ,string struct tag, trying to unmarshal unquoted value into string

On the other hand, when using bool for UnstableReason, an error occurs aswell.

When removing ,string, I get this error:
panic: json: cannot unmarshal bool into Go struct field .data.prices.unstable_reason of type string

The field is not relevant for my purposes, so if there is a way to just let it be nil, this would also be fine.

I have no impact on the API.

Any Ideas? I am relatively new to go.

答案1

得分: 2

你可以使用interface{}类型,如下所示:

type YourMessage struct {
    Unstable       bool        `json:"unstable"`
    UnstableReason interface{} `json:"unstable_reason"`
}

func (m YourMessage) UnstableReasonAsString() string {
    return fmt.Sprint(m.UnstableReason)
}

...

m1 := &YourMessage{}
if err := json.Unmarshal([]byte(messageJson), m1); err != nil {
    fmt.Println("Error", err)
} else {
    fmt.Println("Unstable Reason=", m1.UnstableReasonAsString())
}

这段代码定义了一个名为YourMessage的结构体,其中包含一个Unstable布尔值字段和一个UnstableReason接口类型字段。UnstableReasonAsString方法将UnstableReason字段转换为字符串类型并返回。在主程序中,使用json.Unmarshal函数将JSON数据解析到m1实例中,然后打印出UnstableReason字段的字符串表示。

英文:

You can use interface{} type like as:

type YourMessage struct {
	Unstable       bool        `json:"unstable"`
	UnstableReason interface{} `json:"unstable_reason"`
}

func (m YourMessage) UnstableReasonAsString() string {
	return fmt.Sprint(m.UnstableReason)
}

...
m1 := &YourMessage{}
if err := json.Unmarshal([]byte(messageJson), m1); err != nil {
	fmt.Println("Error", err)
} else {
	fmt.Println("Unstable Reason=", m1.UnstableReasonAsString())
}

huangapple
  • 本文由 发表于 2022年7月24日 18:13:23
  • 转载请务必保留本文链接:https://go.coder-hub.com/73097470.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定