英文:
How to convert a map of two interfaces to a map of two structs
问题
如果我们有一个接口A和一个实现它的结构体a，并且有一个对象aobj，它的类型是接口A，我们可以使用aobj.(*a)进行转换。
然而，如果我有两个接口，比如A和B，以及对应的两个结构体a和b。我还有一个A到B的映射，即map[A]B。是否有一种类似的方式可以将map[A]B转换为map[a]b？
英文:
If we have an interface A and a struct a implementing it, and there's an object aobj which is of the type interface A, we can do the conversion with aobj.(*a).
However, if I have 2 interfaces, say A and B, and two corresponding struct, a and b. And I also have a map between A and B, i.e. map[A]B. Is there any similar conversion from a map[A]B to a map[a]b?
答案1
得分: 1
你必须遍历源映射并对键和值进行类型断言：
func assertMap(m map[A]B) map[a]b {
out := make(map[a]b, len(m))
for k, v := range m {
out[k.(a)] = v.(b)
}
return out
}
英文:
You have to range over the source map and type assert both key and value:
func assertMap(m map[A]B) map[a]b {
out := make(map[a]b, len(m))
for k, v := range m {
out[k.(a)] = v.(b)
}
return out
}
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