英文:
VS Code Regex Search and Replace - whitespace removal between global search of two objects (if and return)
问题
我想删除筛选搜索结果中两个关键词之间的行：
这是我在VS Code中搜索的正则表达式 - ^(?![ \t]*//).*^.*\bif\b.*$\n\n(?![ \t]*//).*^.*\breturn\b.*$
我想删除if和return之间的行，但保留代码，只删除两个关键词之间的行。我知道可以使用$0保留结果，但无法弄清楚下一步，希望能得到帮助！
以下是我想要在结果中的示例：
if o.R == nil {
return nil
}
以下是我不希望在结果中出现的示例：
if err != nil {
return err
}
还有以下不希望在结果中出现的示例：
if foreign.R == nil {
foreign.R = &portfolioBinOperationR{}
return nil
}
在尝试您的解决方案后，这是我的VSCode截图...我做错了什么地方？
英文:
I would like to remove the line in between this filtered search:
Here is the regex that I have in my Search in VS Code - ^(?![ \t]*//).*^.*\bif\b.*$\n\n(?![ \t]*//).*^.*\breturn\b.*$
I would like to get rid of the line in between the if and the return but keep the code, just remove the line in between. I know I can keep the result with the $0 but cant figure out the next part, any help would be much appreciated! 
Here is an example of what I want in the results:
if o.R == nil {
return nil
}
Here are some examples of what I do not want in the results:
if err != nil {
return err
}
Also unwanted in the results:
if foreign.R == nil {
foreign.R = &portfolioBinOperationR{}
return nil
}
Here is the my VSCode after trying your solution...where am I going wrong?
答案1
得分: 1
按照 (if.*?\{)([\s\n]{2,}?)(?=^.*?return) 进行搜索，并用 $1\n 进行替换。请参考正则表达式 演示。
替换前
替换后
英文:
Search by (if.*?\{)([\s\n]{2,}?)(?=^.*?return) and replace with $1\n. See the regex demo.
Before Replacement
After Replacement
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