英文:
Can you put channels in a channel in Go?
问题
你好！以下是你要翻译的内容：
你能在Go语言中创建一个通道的通道吗？
示例：
package mainfunc main() {c := make(chan chan int)go func() {for i := 0; i < 10; i++ {c <- addChannel()}}()}func addChannel() chan int {d := make(chan int)return d}
我只是好奇，因为如果可能的话，这显然在Go编程中可能有一些用途。
英文:
Can you create a channel of channels in Go???<br>
example:
package mainfunc main() {c := make(chan chan int)go func() {for i := 0; i < 10; i++ {c <- addChannel}}()}func addChannel() chan int {d := make(chan int)return d}
I'm just curious, because this obviously could serve some purpose in go programming if it is possible.
答案1
得分: 3
是的，你可以在代码中创建一个通道的通道。在这种情况下，你应该使用make(chan chan int)来创建一个通道的通道，其中通道的类型是int。以下是一个示例代码：
package mainimport "fmt"func main() {c := make(chan chan int)go func() {for i := 0; i < 10; i++ {c <- addChannel()}close(c)}()for ic := range c {for z := range ic {fmt.Println(z)}fmt.Println("done with channel")}}func addChannel() chan int {d := make(chan int)go func() {d <- 1close(d)}()return d}
你可以在这里找到这个示例的在线运行版本。
英文:
Yes you can; the the language specification is a good place to start when you have questions like this.
However while it's possible to create a channel of channels it's not possible to create a channel without a "channel type". So in your code you should use make(chan chan int) that is a channel of channels of int. For example (playground):
package mainimport "fmt"func main() {c := make(chan chan int)go func() {for i := 0; i < 10; i++ {c <- addChannel()}close(c)}()for ic := range c {for z := range ic {fmt.Println(z)}fmt.Println("done with channel")}}func addChannel() chan int {d := make(chan int)go func() {d <- 1close(d)}()return d}
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