英文:
Printing strings and characters as hexadecimal in Go
问题
为什么十六进制格式中的西里尔字母字符串与十六进制格式中的西里尔字符不同？
str := "Э"
fmt.Printf("%x\n", str)
//结果为 d0ad
str := 'Э'
fmt.Printf("%x\n", str)
//结果为 42d
英文:
Why cyrillic strings in hexadecimal format differ from cyrillic chars in hexadecimal format?
str := "Э"
fmt.Printf("%x\n", str)
//result d0ad
str := 'Э'
fmt.Printf("%x\n", str)
//result 42d
答案1
得分: 1
打印一个字符串的十六进制表示会打印出其字节的十六进制表示，而打印一个rune的十六进制表示会打印出它所代表的数字的十六进制表示（rune是int32的别名）。在Go语言中，字符串保存的是文本的UTF-8编码字节序列。在UTF-8表示中，具有数值代码大于127的字符（rune）具有多字节表示。
rune "Э" 在UTF-8中有多字节表示（即[208, 173]），它与32位整数1069 = 0x42d的多字节表示不同。在内存中，整数使用二进制补码表示。
推荐阅读的博文：Go语言中的字符串、字节、rune和字符
英文:
Printing the hexadecimal representation of a string prints the hex representation of its bytes, and printing the hexadecimal representation of a rune prints the hex representation of the number it is an alias to (rune is an alias to int32).
And strings in Go hold the UTF-8 encoded byte sequence of the text. In UTF-8 representation characters (runes) having a numeric code > 127 have multi-byte representation.
The rune Э has multi-byte representation in UTF-8 (being [208, 173]), and it is not the same as the multi-byte representation of the 32-bit integer 1069 = 0x42d. Integers are represented using two's complement in memory.
Recommended blog post: Strings, bytes, runes and characters in Go
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论