英文:
Passing file from JavaScript to Go server
问题
我正在尝试将一组表单值从客户端传递到服务器。表单值包括文件、用户名和其他详细信息。
在服务器端如何解码文件。我在服务器端使用Go语言。我已经创建了一个模型，以便在服务器调用期间解码传递的值。
type Details {PhotographValue os.File `json:"photographvalue"`AdharValue os.File `json:"adharvalue"`UserName string `json:"username"`}
// 解码部分
var clientValues Detailsdecoder := json.NewDecoder(req.Body)err := decoder.Decode(&clientValues)
在clientValues中，我得到了字符串数据，但文件数据为nil。我该如何实现这一点？
PS：我没有使用常规的文件上传方法，因为我还有其他详细信息，而且我在将其传递给服务器之前在JavaScript中对这些详细信息进行了操作。
英文:
I am trying to pass a set of FORM values from client to server. FORM values include files, user names and other details as well.
how do i decode the file in the server side. Here i Use go lang as my server.
i have created a model in my golang so that i can decode the value passed during server call.
type Details {PhotographValue os.File `json:"photographvalue"`AdharValue os.File `json:"adharvalue"`userName string `json:"username"`}
//Decoding part
var clientValues Detailsdecoder := json.NewDecoder(req.Body)err := decoder.Decode(&clientValues)
In clientValues i get string data. but the file data is nil. How can i achieve this?
PS : i am not using the usual file upload method as i have other details too also, i am manipulating those details in javascript before passing on to server.
答案1
得分: 1
如果您将文件作为多部分表单的一部分传递，您应该将其解析为表单，并稍后将其作为单独的 JSON 使用。
func handleForm(w http.ResponseWriter, req *http.Request) {const maxAllowedSizeInBytes = 512 * 1024err := req.ParseMultipartForm(maxAllowedSizeInBytes)if err != nil {// 处理错误w.WriteHeader(http.StatusBadRequest)return}photographValue, _, err := req.FormFile("photographvalue")if err != nil {// 处理错误w.WriteHeader(http.StatusBadRequest)return}adharValue, _, err := req.FormFile("adharvalue")if err != nil {// 处理错误w.WriteHeader(http.StatusBadRequest)return}// photograph := struct{...} {}// json.NewDecoder(file).Decode(&photograph)// 或将其写入文件username := req.FormValue("username")....}
photographValue 和 adharValue 都符合 io.Reader 接口，您可以使用它们来读取 JSON 文件或将其写入系统中的文件。
英文:
If you pass your files as a part of multipart form you should parse it as form and use later as a separate jsons.
func handleForm(w http.ResponseWriter, req *http.Request) {const maxAllowedSizeInBytes = 512 * 1024err := req.ParseMultipartForm(maxAllowedSizeInBytes)if err != nil {// handle error herew.WriteHeader(http.StatusBadRequest)return}photographValue, _, err := req.FormFile("photographvalue")if err != nil {// handle error herew.WriteHeader(http.StatusBadRequest)return}adharValue, _, err := req.FormFile("adharvalue")if err != nil {// handle error herew.WriteHeader(http.StatusBadRequest)return}// photograph := struct{...} {}// json.NewDecoder(file).Decode(&photograph)// or write it to fileusername := req.FormValue("username")....}
photographValue and adharValue conform io.Reader and you can use it to read your json file or write it to file in the system.
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