英文:
Convert four character date string to a date string
问题
我正在接收到一个类似于"1226"的四位字符串作为到期日期。我需要从这个数据中创建一个日期字符串。
到目前为止，我可以获取到月份和年份。我尝试使用文档中提到的time.Parse方法，但我无法弄清楚。
func main() {
dateData := "1226"
month := dateData[:2]
year := dateData[2:]
t, _ := time.Parse("2006-01-02", fmt.Sprintf("20%s-%s-00", year, month))
fmt.Println(t)
// 期望的输出是"2026-12-01"，如果我们能在此基础上再加一个月就更好了，那么它将变成"2027-01-01"
}
英文:
I am receiving the expiry date as a four-letter string like this, "1226"
I need to create a date string from that data.
so far I can get the month and year. tried using time.Parse method was mentioned in the docs but I couldn't figure it out.
func main() {
dateData := "1226"
month := dateData[:2]
year := dateData[2:]
t, _ := time.Parse("2006-01-02", fmt.Sprintf("20%s-%s-00", year, month))
fmt.Println(t)
// expected output is "2026-12-01", and also it's better if we could add one month to this one. then it will become "2027-01-01"
}
答案1
得分: 4
我收到的到期日期是一个四位数的字符串，像这样："1226"
预期的输出是"2026-12-01"
package main
import (
"fmt"
"time"
)
func main() {
date := "1226"
if len(date) == 4 {
date = date[0:2] + "20" + date[2:4]
}
t, err := time.Parse("012006", date)
fmt.Println(t, err)
}
输出结果为：2026-12-01 00:00:00 +0000 UTC
如果我们能够在这个日期上加一个月，那就更好了，它将变成"2027-01-01"
package main
import (
"fmt"
"time"
)
func main() {
date := "1226"
if len(date) == 4 {
date = date[0:2] + "20" + date[2:4]
}
t, err := time.Parse("012006", date)
if err == nil {
t = t.AddDate(0, 1, 0)
}
fmt.Println(t, err)
}
输出结果为：2027-01-01 00:00:00 +0000 UTC
英文:
> I am receiving the expiry date as a four-letter string like this, "1226"
> expected output is "2026-12-01
package main
import (
"fmt"
"time"
)
func main() {
date := "1226"
if len(date) == 4 {
date = date[0:2] + "20" + date[2:4]
}
t, err := time.Parse("012006", date)
fmt.Println(t, err)
}
https://go.dev/play/p/fwfBux1AZQO
2026-12-01 00:00:00 +0000 UTC <nil>
> it's better if we could add one month to this one. then it will become "2027-01-01"
package main
import (
"fmt"
"time"
)
func main() {
date := "1226"
if len(date) == 4 {
date = date[0:2] + "20" + date[2:4]
}
t, err := time.Parse("012006", date)
if err == nil {
t = t.AddDate(0, 1, 0)
}
fmt.Println(t, err)
}
https://go.dev/play/p/xCAyxPdRjib
2027-01-01 00:00:00 +0000 UTC <nil>
答案2
得分: -1
这个对你有用吗？
https://go.dev/play/p/hrwVa_CvGYL
func DateStringFromTime(t time.Time) string {
return (strings.Split(fmt.Sprint(t), " "))[0]
}
func TimeFromMMYY(dateData string) (time.Time, error) {
t := time.Time{}
if len(dateData) != 4 {
return t, errors.New("bad date string")
}
month := dateData[:2]
year := dateData[2:]
m, err := strconv.Atoi(month)
if err != nil {
return t, err
}
y, err := strconv.Atoi(year)
if err != nil {
return t, err
}
loc := time.UTC // or time.Local
t = time.Date(2000+y, time.Month(m), 1, 0, 0, 0, 0, loc)
return t, nil
}
func main() {
dateData := "1226"
t, _ := TimeFromMMYY(dateData)
fmt.Println(DateStringFromTime(t)) // prints 2026-12-01
// add a month
t = t.AddDate(0, 1, 0)
fmt.Println(DateStringFromTime(t)) // prints 2027-01-01
}
英文:
Does this work for you?
https://go.dev/play/p/hrwVa_CvGYL
func DateStringFromTime(t time.Time) string {
return (strings.Split(fmt.Sprint(t), " "))[0]
}
func TimeFromMMYY(dateData string) (time.Time, error) {
t := time.Time{}
if len(dateData) != 4 {
return t, errors.New("bad date string")
}
month := dateData[:2]
year := dateData[2:]
m, err := strconv.Atoi(month)
if err != nil {
return t, err
}
y, err := strconv.Atoi(year)
if err != nil {
return t, err
}
loc := time.UTC // or time.Local
t = time.Date(2000+y, time.Month(m), 1, 0, 0, 0, 0, loc)
return t, nil
}
func main() {
dateData := "1226"
t, _ := TimeFromMMYY(dateData)
fmt.Println(DateStringFromTime(t)) // prints 2026-12-01
// add a month
t = t.AddDate(0, 1, 0)
fmt.Println(DateStringFromTime(t)) // prints 2027-01-01
}
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