英文:
how to make Goroutine not Concurrency if Same Function
问题
有没有办法让goroutine按顺序执行（一个接一个）如果它们是相同的函数？
我一开始并不打算使用goroutine。然而，在TCP中使用"os/exec"函数会导致TCP强制停止。因此，我使用goroutine来避免崩溃。但是我仍然希望它们按顺序执行，而不是并发执行。这是我的代码。
func handleTCP(conn net.Conn) {defer conn.Close()fmt.Println("handle TCP function")for {wg := new(sync.WaitGroup)wg.Add(1)go func() {cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}cmd := exec.Command("calib.exe", cmdArgs...)wg.Done()}()}}
英文:
Is there any way to make goroutine execute one after another ( one by one) if it was the same function?
I didn't mean to use goroutine firstly. However, "os/exec" function in TCP will cause the tcp forced to stop. Thus I use goroutine to avoid crashing. But I still want them to execute by order, instead of concurrently. Here is my code.
func handleTCP(conn net.Conn) {defer conn.Close()fmt.Println("handle TCP function")for {wg := new(sync.WaitGroup)wg.Add(1)go func() {cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}cmd := exec.Command("calib.exe", cmdArgs...)wg.Done()}()}}
答案1
得分: 0
尝试将锁放入函数中，这样可以使它们的执行顺序变为串行。但要记住，wg.Done()必须在函数的第一行的defer下面。
类似这样的代码：
var mu sync.Mutexfunc handleTCP(conn net.Conn) {defer conn.Close()fmt.Println("handle TCP function")for {wg := new(sync.WaitGroup)wg.Add(1)go func() {defer wg.Done()mu.Lock()defer mu.Unlock()cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}cmd := exec.Command("calib.exe", cmdArgs...)// 执行命令}()}}
英文:
Try to put the lock into function, it makes theirs execution sequential. But remember about wg.Done() must be under defer at first line of the function.
Something like this:
var mu sync.Mutexfunc handleTCP(conn net.Conn) {defer conn.Close()fmt.Println("handle TCP function")for {wg := new(sync.WaitGroup)wg.Add(1)go func() {defer wg.Done()mu.Lock()defer mu.UnLock()cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}cmd := exec.Command("calib.exe", cmdArgs...)}()}}
答案2
得分: 0
你可以使用锁（locks）来限制对资源的访问，使其一次只能由一个线程访问，如下所示：
i := 1iLock := &sync.Mutex{}for {go func() {iLock.Lock()fmt.Printf("i的值：%d\n", i)iLock.Unlock()}()}
更多示例请参考这里。
不确定你使用WaitGroup是为了什么目的。如果是为了实现你想要的顺序执行，那么可以将其移除。
英文:
You can use locks to limit access to a resource to one thread at a time as follows
i := 1iLock = &sync.Mutex{}for {go func() {iLock.Lock()fmt.Printf("Value of i: %d\n", i)iLock.Unlock()}}
More examples here
Not sure what you are using the WaitGroup for. If it is to achieve the sequentiality you desire, then it can be removed.
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