如何使Goroutine在相同函数中不并发执行。

huangapple go评论94阅读模式
英文:

how to make Goroutine not Concurrency if Same Function

问题

有没有办法让goroutine按顺序执行(一个接一个)如果它们是相同的函数?

我一开始并不打算使用goroutine。然而,在TCP中使用"os/exec"函数会导致TCP强制停止。因此,我使用goroutine来避免崩溃。但是我仍然希望它们按顺序执行,而不是并发执行。这是我的代码。

func handleTCP(conn net.Conn) {
    defer conn.Close()
    fmt.Println("handle TCP function")
    for {
        wg := new(sync.WaitGroup)
        wg.Add(1)
        go func() {
            cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}
            cmd := exec.Command("calib.exe", cmdArgs...)
            wg.Done()
        }()
    }
}
英文:

Is there any way to make goroutine execute one after another ( one by one) if it was the same function?

I didn't mean to use goroutine firstly. However, "os/exec" function in TCP will cause the tcp forced to stop. Thus I use goroutine to avoid crashing. But I still want them to execute by order, instead of concurrently. Here is my code.

func handleTCP(conn net.Conn) {
    defer conn.Close()
    	fmt.Println("handle TCP function")
    	for {
              wg := new(sync.WaitGroup)
		      wg.Add(1)
              go func() {
			      cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}
    		      cmd := exec.Command("calib.exe", cmdArgs...)
			      wg.Done()
		      }()
              
        }
}

答案1

得分: 0

尝试将锁放入函数中,这样可以使它们的执行顺序变为串行。但要记住,wg.Done()必须在函数的第一行的defer下面。

类似这样的代码:

var mu sync.Mutex

func handleTCP(conn net.Conn) {
    defer conn.Close()
    fmt.Println("handle TCP function")
    for {
        wg := new(sync.WaitGroup)
        wg.Add(1)
        go func() {
            defer wg.Done()
            mu.Lock()
            defer mu.Unlock()
            cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}
            cmd := exec.Command("calib.exe", cmdArgs...)
            // 执行命令
        }()
    }
}
英文:

Try to put the lock into function, it makes theirs execution sequential. But remember about wg.Done() must be under defer at first line of the function.
Something like this:

var mu sync.Mutex

func handleTCP(conn net.Conn) {
    defer conn.Close()
        fmt.Println("handle TCP function")
        for {
              wg := new(sync.WaitGroup)
              wg.Add(1)
              go func() {
                  defer wg.Done()
                  mu.Lock()
                  defer mu.UnLock()
                  cmdArgs := []string{temp_str, test_press, gh, "sample.csv"}
                  cmd := exec.Command("calib.exe", cmdArgs...)
                  
              }()
              
        }
}

答案2

得分: 0

你可以使用锁(locks)来限制对资源的访问,使其一次只能由一个线程访问,如下所示:

i := 1
iLock := &sync.Mutex{}

for {
    go func() {
        iLock.Lock()
        fmt.Printf("i的值:%d\n", i)
        iLock.Unlock()
    }()
}

更多示例请参考这里

不确定你使用WaitGroup是为了什么目的。如果是为了实现你想要的顺序执行,那么可以将其移除。

英文:

You can use locks to limit access to a resource to one thread at a time as follows

i := 1
iLock = &sync.Mutex{}

for {
    go func() {
        iLock.Lock()
        fmt.Printf("Value of i: %d\n", i)
        iLock.Unlock()
    }
}

More examples here

Not sure what you are using the WaitGroup for. If it is to achieve the sequentiality you desire, then it can be removed.

huangapple
  • 本文由 发表于 2022年4月21日 10:41:32
  • 转载请务必保留本文链接:https://go.coder-hub.com/71948310.html
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