英文:
How do I convert post request body to query string format on go fasthttp/gofiber?
问题
这是我使用Get请求的代码:
app.Get("/", func(c *fiber.Ctx) error {
fmt.Println(string(c.Request().URI().QueryString()))
return c.SendString("Ok!")
})
我得到了以下输出:
hello=12&sdsdf=324
我想在POST请求中做同样的事情。我尝试了string(c.Body())
,但我得到了以下输出:
----------------------------948304762891896410291124
Content-Disposition: form-data; name="hello"
ge
----------------------------948304762891896410291124
Content-Disposition: form-data; name="ge"
dsfs
----------------------------948304762891896410291124--
如何获得一个类似于查询字符串格式的POST输出。POST参数可以是任何内容和任意数量。
英文:
This is what I'm doing with Get requests
app.Get("/", func(c *fiber.Ctx) error {
fmt.Println(string(c.Request().URI().QueryString()))
return c.SendString("Ok!")
})
I'm getting the following output
hello=12&sdsdf=324
I want to do the same for POST request. I tried string(c.Body())
but I got output like the following
----------------------------948304762891896410291124
Content-Disposition: form-data; name="hello"
ge
----------------------------948304762891896410291124
Content-Disposition: form-data; name="ge"
dsfs
----------------------------948304762891896410291124--
How can I get a query string format out put for POST. The post parameters can be anything and any number.
答案1
得分: 3
你可以尝试使用BodyParser
方法,文档链接在https://docs.gofiber.io/api/ctx#bodyparser
type Person struct {
Name string `json:"name" xml:"name" form:"name"`
}
app.Post("/", func(c *fiber.Ctx) error {
p := new(Person)
if err := c.BodyParser(p); err != nil {
return err
}
log.Println(p.Name)
return nil
})
英文:
You could try BodyParser
method, the Document Link at https://docs.gofiber.io/api/ctx#bodyparser
type Person struct {
Name string `json:"name" xml:"name" form:"name"`
}
app.Post("/", func(c *fiber.Ctx) error {
p := new(Person)
if err := c.BodyParser(p); err != nil {
return err
}
log.Println(p.Name)
return nil
})
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论