英文:
Replace regular expression matches with values of a slice
问题
我的目标是替换字符串中正则表达式的匹配项。我的代码如下：
func ReplaceBase64ToDecodedImage(data string) string {imageSrc := make(chan []string)go base64toPng(content, imageSrc)result := <-imageSrcfmt.Println("received string: ", result)re := regexp.MustCompile(`data:image/png;base64,[^]+['"]([^'"]+)['"]`)s := re.ReplaceAllString(data, "slice replacement values")return s}
我通过通道将字符串切片流式传输到替换函数中。在JavaScript中，可以使用shift()函数轻松实现这一点：
const paragraph = 'This ??? is ??? and ???. Have you seen the ????';const regex = /(\?\?\?)/g;const replacements = ['cat', 'cool', 'happy', 'dog'];const found = paragraph.replace(regex, () => replacements.shift());console.log(found);
但是我在Go中没有找到类似的方法，而且ReplaceAllString()函数不接受字符串切片。在golang中是否有实现这一功能的方法？我对golang非常陌生，所以对它的功能还不太了解。
英文:
My goal is to replace matches of a regular expression in a string. My code:
func ReplaceBase64ToDecodedImage(data string) string {imageSrc := make(chan []string)go base64toPng(content, imageSrc)result := <-imageSrcfmt.Println("received string: ", result)re := regexp.MustCompile(`data:image/png;base64,[^]+["']([^"']+)["']`)s := re.ReplaceAllString(data, "slice replacement values")return s}
I'm streaming slice of strings via channel to replacement function. In Javascript this can be done easily using shift() function:
const paragraph = 'This ??? is ??? and ???. Have you seen the ????';const regex = /(\?\?\?)/g;const replacements = ['cat', 'cool', 'happy', 'dog'];const found = paragraph.replace(regex, () => replacements.shift());console.log(found);
but I haven't found analog for this in go and ReplaceAllString() doesn't accept slices of strings. Is there a way to achieve this in golang? I'm very new to golang, so don't know much about it's capabilities yet.
答案1
得分: 0
你可以使用*regexp.Regexp上可用的ReplaceAllStringFunc函数。要实现类似JavaScript中的功能，可以这样做：
input := "This ??? is ??? and ???. Have you seen the ????"replacements := []string{"cat", "cl", "happyjaxvin", "dog"}r, _ := regexp.Compile(`\?\?\?`)res := r.ReplaceAllStringFunc(input, func(_ string) string {var repl stringrepl, replacements = replacements[0], replacements[1:]return repl})fmt.Println(res)
英文:
You can use ReplaceAllStringFunc function available on *regexp.Regexp. To achieve the similar functionality you did in JavaScript like this:
input := "This ??? is ??? and ???. Have you seen the ????"replacements := []string{"cat", "cl", "happyjaxvin", "dog"}r, _ := regexp.Compile(`\?\?\?`)res := r.ReplaceAllStringFunc(input, func(_ string) string {var repl stringrepl, replacements = replacements[0], replacements[1:]return repl})fmt.Println(res)
答案2
得分: 0
你可以通过ReplaceAllStringFunc方法来实现。使用这个方法，我们可以创建一个函数，遍历切片并返回每个值：
import ("fmt""regexp")func main() {paragraph := "This ??? is ??? and ???. Have you seen the ????"re := regexp.MustCompile(`(\?\?\?)`)replacements := []string{"cat", "cool", "happy", "dog"}count := 0replace := func(string) string {count++return replacements[count-1]}s := re.ReplaceAllStringFunc(paragraph, replace)fmt.Println(s)}
这段代码会将"???"替换为切片中的对应值，输出结果为："This cat is cool and happy. Have you seen the dog?"
英文:
You can do this via the ReplaceAllStringFunc method. Using this we can create a method that will iterate through the slice and return each value:
<pre><code>
import (
"fmt"
"regexp"
)
func main() {
paragraph := "This ??? is ??? and ???. Have you seen the ????"
re := regexp.MustCompile((\?\?\?))
replacements := []string{"cat", "cool", "happy", "dog"}
count := 0
replace := func(string) string {
count++
return replacements[count-1]
}
s := re.ReplaceAllStringFunc(paragraph, replace)
fmt.Println(s)
}
</code></pre>
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