英文:
In Golang How to generate a random string of random length within range without integers
问题
我尝试使用正则表达式从生成的字符串中删除整数，但这样做不能给我所需范围内的长度（很多长度会小于最小值）。
package main
import (
"fmt"
"log"
"math/rand"
"regexp"
"time"
)
func randomString(length int) string {
rand.Seed(time.Now().UnixNano())
b := make([]byte, length)
rand.Read(b)
return fmt.Sprintf("%x", b)[:length]
}
func randomLength(minL, maxL int) int {
rand.Seed(time.Now().UnixNano())
return rand.Intn(maxL-minL) + minL
}
func main() {
reg, err := regexp.Compile("[^a-zA-Z]+")
if err != nil {
log.Fatal(err)
}
for i := 0; i < 10; i++ {
processedString := reg.ReplaceAllString(randomString(randomLength(8, 16)), "")
println(processedString)
}
}
编辑：
当我搜索问题时，我错过了详细的@icza在那个问题中的回答。这里是他的回答。
英文:
I tried to remove the integer from the generated string with regex but this will not give me the length within the range required( many will be less than the minimum )
package main
import (
"fmt"
"log"
"math/rand"
"regexp"
"time"
)
func randomString(length int) string {
rand.Seed(time.Now().UnixNano())
b := make([]byte, length)
rand.Read(b)
return fmt.Sprintf("%x", b)[:length]
}
func randomLength(minL, maxL int) int {
rand.Seed(time.Now().UnixNano())
return rand.Intn(maxL-minL) + minL
}
func main() {
reg, err := regexp.Compile("[^a-zA-Z]+")
if err != nil {
log.Fatal(err)
}
for i := 0; i < 10; i++ {
processedString := reg.ReplaceAllString(randomString(randomLength(8, 16)), "")
println(processedString)
}
}
Edit:
when I searched for the question I missed detailed @icza answer in that question.
答案1
得分: 3
var seededRand = rand.New(rand.NewSource(time.Now().UnixNano()))
func StringWithCharset(length int, charset string) string {
b := make([]byte, length)
for i := range b {
b[i] = charset[seededRand.Intn(len(charset)-1)]
}
return string(b)
}
func main() {
rangeStart := 0
rangeEnd := 10
offset := rangeEnd - rangeStart
randLength := seededRand.Intn(offset) + rangeStart
charSet := "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"
randString := StringWithCharset(randLength, charSet)
}
var seededRand = rand.New(rand.NewSource(time.Now().UnixNano()))
func StringWithCharset(length int, charset string) string {
b := make([]byte, length)
for i := range b {
b[i] = charset[seededRand.Intn(len(charset)-1)]
}
return string(b)
}
func main() {
rangeStart := 0
rangeEnd := 10
offset := rangeEnd - rangeStart
randLength := seededRand.Intn(offset) + rangeStart
charSet := "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"
randString := StringWithCharset(randLength, charSet)
}
英文:
var seededRand = rand.New(rand.NewSource(time.Now().UnixNano()))
func StringWithCharset(length int, charset string) string {
b := make([]byte, length)
for i := range b {
b[i] = charset[seededRand.Intn(len(charset)-1)]
}
return string(b)
}
func main() {
rangeStart := 0
rangeEnd := 10
offset := rangeEnd - rangeStart
randLength := seededRand.Intn(offset) + rangeStart
charSet := "aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ"
randString := StringWithCharset(randLength, charSet)
}
答案2
得分: 1
你只需要定义你正在使用的字母表。类似以下的方式（你可以在Go Playground中进行调试）。
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
var alphabet []rune = []rune("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")
rs := randomString(20, alphabet)
fmt.Printf("这是相当随机的字符串：%s\n", rs)
}
func randomString(n int, alphabet []rune) string {
alphabetSize := len(alphabet)
var sb strings.Builder
for i := 0; i < n; i++ {
ch := alphabet[rand.Intn(alphabetSize)]
sb.WriteRune(ch)
}
s := sb.String()
return s
}
英文:
You just need to define the alphabet that you're using. Something like the following (You can fiddle with it here in the Go Playground).
package main
import (
"fmt"
"math/rand"
"strings"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
var alphabet []rune = []rune("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz")
rs := randomString(20, alphabet)
fmt.Printf("This is pretty random: %s\n", rs)
}
func randomString(n int, alphabet []rune) string {
alphabetSize := len(alphabet)
var sb strings.Builder
for i := 0; i < n; i++ {
ch := alphabet[rand.Intn(alphabetSize)]
sb.WriteRune(ch)
}
s := sb.String()
return s
}
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