英文:
How to split '_' with one more any one character in golang?
问题
如何使用任意一个字符来分割'_'?
例如,
var one = 6221c62c67bc2a98ec6f713b_h32
-> strings.Split(one, "_h")
var one = 12345c62c67bc2a98ec6f723c_c32
-> strings.Split(one, "_c")
var one = 12345c62c67bc2a98ec6f723c_s32
-> strings.Split(one, "_s")
如何将它们组合起来?(使用正则表达式?还是其他想法)
strings.Split(one, "_??")
英文:
How to split '_' with any one character?
for Examples,
var one = 6221c62c67bc2a98ec6f713b_h32
-> strings.Split(one, "_h")
var one = 12345c62c67bc2a98ec6f723c_c32
-> strings.Split(one, "_c")
var one = 12345c62c67bc2a98ec6f723c_s32
-> strings.Split(one, "_s")
How to combine these? (use regex? or any idea)
strings.Split(one, "_??")
答案1
得分: 1
你可以使用正则表达式:_[a-zA-Z]
,例如:
str := "6221c62c67bc2a98ec6f713b_h32"
a := regexp.MustCompile("_[a-zA-Z]")
fmt.Println(a.Split(str, 2))
英文:
You can use the regex: _[a-zA-Z]
, for eg
str := "6221c62c67bc2a98ec6f713b_h32"
a := regexp.MustCompile("_[a-zA-Z]")
fmt.Println(a.Split(str, 2))
答案2
得分: 0
你可以使用字符串的Replace方法:
strings.Replace("6221c62c67bc2a98ec6f713b_h32", "_h", " ", 1)
英文:
You can use string.Replace:
strings.Replace("6221c62c67bc2a98ec6f713b_h32", "_h", " ", 1)
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库,让每个人都能够通过互相帮助和分享经验来进步。
评论