英文:
Calling function names from a slice and return a value
问题
我想调用存储在切片中的一系列函数名称。下面的代码片段目前可以工作，但我需要从这些函数中返回一个值。不幸的是，我不知道如何调用这些函数并存储返回值。有什么想法吗？
这是我目前正在处理的代码：
package mainfunc A(x int) int {return x + 1}func B(x int) int {return x + 2}func C(x int) int {return x + 3}func main() {x := 10type fs func(x int) intf := []fs{A, B, C}fns := make([]func(), 3)for a, _ := range f {a := afns[a] = func() {f[a](x)}}for _, f := range fns {f()}}
英文:
I want to call a number of function names stored in a slice. The code snippet below works so far but I need to return a value from those functions. Unfortunately I don't get it to work because I don't know to to call those functions and store the return value. Any ideas?
This is the code I'm currently working on:
package mainfunc A(x int) int {return x + 1}func B(x int) int {return x + 2}func C(x int) int {return x + 3}func main() {x := 10type fs func(x int) intf := []fs{A, B, C}fns := make([]func(), 3)for a, _ := range f {a := afns[a] = func() {f[a](x)}}for _, f := range fns {f()}}
答案1
得分: 1
你叫它...
for a, _ := range f {a := afns[a] = func() {f[a](x) // 在这里}}
这是playground。
英文:
You have call it...
for a, _ := range f {a := afns[a] = func() {f[a](x) // in this}}
here is the playground
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