英文:
How to create map variable from string literal in Golang?
问题
我有一个准备好的地图结构，它是一个字符串文字。请注意，它不是 JSON！（看一下块的最后一个元素中的逗号）
dict := `{"ru": {"test_key": "Тестовый ключ","some_err": "Произошла ошибка",},"en": {"test_key": "Test key","some_err": "Error occurs",},}`
我想将这个字符串转换为地图类型（map[string]map[string]string）的实际值。我需要它用于测试。这可能吗？
英文:
I have a prepared map structure as a string literal. Notice, it is not a JSON! (look at commas in the last elements of blocks)
dict := `{"ru": {"test_key": "Тестовый ключ","some_err": "Произошла ошибка",},"en": {"test_key": "Test key","some_err": "Error occurs",},}`
I want to transform this string to real value of map type (map[string]map[string]string). I need it for tests. Is it possible?
答案1
得分: 2
如果这只是用于测试，我会从源字符串中删除“不必要”的逗号，并使用JSON解组。
要删除不必要的逗号：我会使用正则表达式,\s*}，将其替换为单个}。
例如：
dict = regexp.MustCompile(`,\s*}`).ReplaceAllLiteralString(dict, "}")var m map[string]map[string]stringif err := json.Unmarshal([]byte(dict), &m); err != nil {panic(err)}fmt.Println(m)
输出结果（在Go Playground上尝试）：
map[en:map[some_err:Error occurs test_key:Test key] ru:map[some_err:Произошла ошибка test_key:Тестовый ключ]]
英文:
If this is just for testing, I would remove the "unneeded" commas from the source string and use JSON unmarshaling.
To remove the unneeded commas: I'd use the regexp ,\s*}, and replace it with a single }.
For example:
dict = regexp.MustCompile(`,\s*}`).ReplaceAllLiteralString(dict, "}")var m map[string]map[string]stringif err := json.Unmarshal([]byte(dict), &m); err != nil {panic(err)}fmt.Println(m)
Output (try it on the Go Playground):
map[en:map[some_err:Error occurs test_key:Test key] ru:map[some_err:Произошла ошибка test_key:Тестовый ключ]]
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论