如何在Golang中将一组数组(字符串)转换为多维切片?

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英文:

How do I take a set of arrays (strings) and create a multidimensional slice of those arrays in Golang?

问题

我正在尝试实现一个函数,当传入一个字符串数组时,它会创建一个数组切片,并将每个传入的数组添加到其中。它将返回所有传入数组的最终切片。

作为一个测试,我初始化了4个数组,并尝试创建一个能够实现这一功能的函数。然而,它失败得相当惨。以下是我目前的代码。不确定如何继续。

func main() {
    array1 := []string{"x", "o", "x", "_", "_"}
    array2 := []string{"0", "o", "x", "_", "_"}
    array3 := []string{"o", "o", "o", "_", "_"}
    array4 := []string{"o", "o", "o", "o", "o"}

    FinalSlice(array1)
    FinalSlice(array2)
    FinalSlice(array3)
    fmt.Println(FinalSlice(array4))
}

func FinalSlice(array []string) [][]string {
    var slice [][]string
    for i, _ := range slice {
        slice[i] = array
    }
    return slice
}

目前的输出是:

[]
英文:

I am trying to implement a function, that when passed an array of strings, it creates a slice of arrays, and adds to it every array that is passed. It would return the final slice of all arrays that was passed.

Just as a test, I initialized 4 arrays and tried to create a function that would do just this. However, it fails quite miserably. This is what I have so far. Not sure how to go about this.

func main() {
	array1 := []string{"x", "o", "x", "_", "_"}
	array2 := []string{"0", "o", "x", "_", "_"}
	array3 := []string{"o", "o", "o", "_", "_"}
	array4 := []string{"o", "o", "o", "o", "o"}

	FinalSlice(array1)
	FinalSlice(array2)
	FinalSlice(array3)
	fmt.Println(FinalSlice(array4))

}

func FinalSlice(array []string) [][]string {
	var slice [][]string
	for i, _ := range slice {
		slice[i] = array
	}
	return slice

}

Right now this is the output:

[]

答案1

得分: 2

这是因为你在一个空切片上进行循环,而空切片没有元素。

所以你的循环

for i, _ := range slice {}

实际上不会执行任何迭代(这就是为什么最终得到一个空数组)。

我不太明白你想要实现的确切结果,但如果你想将数组连接成一个多维数组,你可以使用下面的代码:

package main

import "fmt"

func AppendSlice(source [][]string, value []string) [][]string {
	return append(source, value)
}

func main() {
	array1 := []string{"x", "o", "x", "_", "_"}
	array2 := []string{"0", "o", "x", "_", "_"}
	array3 := []string{"o", "o", "o", "_", "_"}
	array4 := []string{"o", "o", "o", "o", "o"}

	var finalArray [][]string

	finalArray = AppendSlice(finalArray, array1)
	finalArray = AppendSlice(finalArray, array2)
	finalArray = AppendSlice(finalArray, array3)
	finalArray = AppendSlice(finalArray, array4)

	// [[x o x _ _] [0 o x _ _] [o o o _ _] [o o o o o]]
	fmt.Println(finalArray) 
}

这个代码可以有很多改进的地方,你可以随意尝试这个解决方案:https://go.dev/play/p/vXvqlRZuOUI

英文:

That is because you loop through an empty slice, which has no elements.

So your loop

for i, _ := range slice {}

will actually run 0 iteration (that's why you end up with an empty array).

I don't understand the exact result you want to achieve, but if you want to concat arrays into a multi-dimensional one, you can use the below code:

package main

import "fmt"

func AppendSlice(source [][]string, value []string) [][]string {
	return append(source, value)
}

func main() {
	array1 := []string{"x", "o", "x", "_", "_"}
	array2 := []string{"0", "o", "x", "_", "_"}
	array3 := []string{"o", "o", "o", "_", "_"}
	array4 := []string{"o", "o", "o", "o", "o"}

	var finalArray [][]string

	finalArray = AppendSlice(finalArray, array1)
	finalArray = AppendSlice(finalArray, array2)
	finalArray = AppendSlice(finalArray, array3)
	finalArray = AppendSlice(finalArray, array4)

	// [[x o x _ _] [0 o x _ _] [o o o _ _] [o o o o o]]
	fmt.Println(finalArray) 
}

This may be improved in many ways, feel free to play around with this solution: https://go.dev/play/p/vXvqlRZuOUI

答案2

得分: 1

可以这样说:

func bundleSlices(slices ...[]int) [][]int {
	return slices
}

然后:

package main

import "fmt"

func main() {
	arr1 := []int{1, 2, 3}
	arr2 := []int{4, 5, 6}
	arr3 := []int{7, 8, 9}

	bundled := bundleSlices(arr1, arr2, arr3)

	fmt.Println(bundled)
}

得到结果:

[[1 2 3] [4 5 6] [7 8 9]]
英文:

Couldn't one just say something like

func bundleSlices( slices ...[]int) [][]int {
	return slices
}

And then:

package main

import "fmt"

func main() {
	arr1 := []int{1, 2, 3}
	arr2 := []int{4, 5, 6}
	arr3 := []int{7, 8, 9}

	bundled := bundleSlices( arr1, arr2, arr3 )

	fmt.Println(bundled)

}

to get

[[1 2 3] [4 5 6] [7 8 9]]

huangapple
  • 本文由 发表于 2022年2月9日 01:11:48
  • 转载请务必保留本文链接:https://go.coder-hub.com/71037981.html
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