由于响应结构的微小变化,重复调用JSON解码器。

huangapple go评论96阅读模式
英文:

Calling JSON decoder repetitvely because of small change in response structure

问题

我已经将Github和Google身份验证系统添加到我的Web应用程序中。我希望在这两种情况下都能获取用户的电子邮件地址。我尝试创建一个函数,该函数将进行API请求并获取电子邮件地址。我遇到了一个问题,即Google返回一个JSON对象,而Github返回一个JSON数组作为响应。我无法找到一种方法来避免调用JSON解码器两次,因为我不能为它们都使用相同类型的变量。

// 发送一个请求到API,并通过将HTTP头“Authorization”设置为authHeader值来授权
func getUserEmail(endpoint, authHeader, provider string) (string, error) {
    var email string       // 在这里存储用户电子邮件
    var client http.Client // 创建客户端以便我们可以修改请求头

    // 创建一个GET请求到端点
    req, err := http.NewRequest("GET", endpoint, nil)
    if err != nil {
        return "", err
    }

    // 通过使用HTTP头来授权请求
    req.Header.Add("Authorization", authHeader)

    // 将数据返回为JSON
    req.Header.Add("accept", "application/json")

    // 发送请求
    resp, err := client.Do(req)
    if err != nil {
        fmt.Println("Internet connection or client policy error")
        return "", err
    }
    defer resp.Body.Close()

    if provider == "google" {
        var response map[string]interface{}

        err = json.NewDecoder(resp.Body).Decode(&response)
        if err != nil {
            fmt.Println("Error occured during decoding access token response")
            return "", err
        }

        email = response["email"].(string)

    } else if provider == "github" {
        var response []map[string]interface{}

        err = json.NewDecoder(resp.Body).Decode(&response)
        if err != nil {
            fmt.Println("Error occured during decoding access token response")
            return "", err
        }

        email = response[0]["email"].(string)
    } else {
        return "", errors.New("invalid provider")

    }

    return email, nil
}
英文:

I have added Github and Google authentication system to my web application. I am looking to get user email in both of these cases. I tried to make a one function which would make the API request and get the email.<br>
I ran into an issue when Google returned a JSON object and Github a JSON array as a response. <br>
I cant figure out a way how I could avoid calling the JSON decoder twice as I cant have a same type variable for both of them.

// Sends a request to the API and
// authorizes it by setting HTTP header &quot;Authorization&quot; to authHeader value
func getUserEmail(endpoint, authHeader, provider string) (string, error) {
var email string       // Store user email here
var client http.Client // Create client so we can modify request headers
// Create a GET request to the endpoint
req, err := http.NewRequest(&quot;GET&quot;, endpoint, nil)
if err != nil {
return &quot;&quot;, err
}
// Authorize the request by using the HTTP header
req.Header.Add(&quot;Authorization&quot;, authHeader)
// Give the data back as JSON
req.Header.Add(&quot;accept&quot;, &quot;application/json&quot;)
// Send the request
resp, err := client.Do(req)
if err != nil {
fmt.Println(&quot;Internet connection or client policy error&quot;)
return &quot;&quot;, err
}
defer resp.Body.Close()
if provider == &quot;google&quot; {
var response map[string]interface{}
err = json.NewDecoder(resp.Body).Decode(&amp;response)
if err != nil {
fmt.Println(&quot;Error occured during decoding access token response&quot;)
return &quot;&quot;, err
}
email = response[&quot;email&quot;].(string)
} else if provider == &quot;github&quot; {
var response []map[string]interface{}
err = json.NewDecoder(resp.Body).Decode(&amp;response)
if err != nil {
fmt.Println(&quot;Error occured during decoding access token response&quot;)
return &quot;&quot;, err
}
email = response[0][&quot;email&quot;].(string)
} else {
return &quot;&quot;, errors.New(&quot;invalid provider&quot;)
}
return email, nil
}

答案1

得分: 2

你可以将其解组为var response interface{}。一旦JSON解组完成,你可以对response进行类型断言,以检查它是[]interface{}还是map[string]interface{},然后根据情况进行处理。

var email string
var response interface{}
if err := json.NewDecoder(r.Body).Decode(&response); err != nil {
    return err
}

// 如果你确定响应内容的结构,在给定其类型的情况下,总是符合你的预期,你可以使用快速且简单的类型切换/断言。
switch v := response.(type) {
case []interface{}:
    email = v[0].(map[string]interface{})["email"].(string)
case map[string]interface{}:
    email = v["email"].(string)
}

// 但是!如果你不确定,如果API没有提供保证,那么你应该使用逗号-ok惯用法来防止恐慌。
if s, ok := response.([]interface{}); ok && len(s) > 0 {
    if m, ok := s[0].(map[string]interface{}); ok && len(m) > 0 {
        email, _ = m["email"].(string)
    }
} else if m, ok := response.(map[string]interface{}); ok && len(m) > 0 {
    email, _ = m["email"].(string)
}

你还可以根据提供者的值预先分配一个指针到预期类型,并将请求体解组到其中,这将减少所需的类型断言的数量,但需要进行指针解引用。

var email string
var response interface{}
if provider == "google" {
    response = new(map[string]interface{})
} else if provider == "github" {
    response = new([]map[string]interface{})
}
if err := json.NewDecoder(r.Body).Decode(response); err != nil {
    return err
}

switch v := response.(type) {
case *[]map[string]interface{}:
    email = (*v)[0]["email"].(string) // 不需要断言切片元素的类型
case *map[string]interface{}:
    email = (*v)["email"].(string)
}
英文:

You can unmarshal into var response interface{}. Once the json is unmarshaled you can do a type assertion on the response to check if it's []interface{} or map[string]interface{} and go from there.

var email string
var response interface{}
if err := json.NewDecoder(r.Body).Decode(&amp;response); err != nil {
    return err
}

// If you are sure that the structure of the content of the response,
// given its type, is always what you expect it to be, you can use a
// quick-and-dirty type switch/assertion.
switch v := response.(type) {
case []interface{}:
    email = v[0].(map[string]interface{})[&quot;email&quot;].(string)
case map[string]interface{}:
    email = v[&quot;email&quot;].(string)
}

// But! If you&#39;re not sure, if the APIs don&#39;t provide a guarantee,
// then you should guard against panics using the comma-ok idiom
// at every step.
if s, ok := response.([]interface{}); ok &amp;&amp; len(s) &gt; 0 {
    if m, ok := s[0].(map[string]interface{}); ok &amp;&amp; len(m) &gt; 0 {
        email, _ = m[&quot;email&quot;].(string)
    }
} else if m, ok := response.(map[string]interface{}); ok &amp;&amp; len(m) &gt; 0 {
    email, _ = m[&quot;email&quot;].(string)
}

You can also pre-allocate a pointer to the expected type based on the provider value and unmarshal the request body into that, this will reduce the number of type assertions necessary but will require pointer-dereferencing.

var email string
var response interface{}
if provider == &quot;google&quot; {
    response = new(map[string]interface{})
} else if provider == &quot;github&quot; {
    response = new([]map[string]interface{})
}
if err := json.NewDecoder(r.Body).Decode(response); err != nil {
    return err
}

switch v := response.(type) {
case *[]map[string]interface{}:
    email = (*v)[0][&quot;email&quot;].(string) // no need to assert the slice element&#39;s type
case *map[string]interface{}:
    email = (*v)[&quot;email&quot;].(string)
}

huangapple
  • 本文由 发表于 2022年1月27日 15:44:08
  • 转载请务必保留本文链接:https://go.coder-hub.com/70874903.html
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