英文:
Why slice length greater than capacity gives runtime error?
问题
创建了一个容量小于长度的切片
package main
import "fmt"
func main() {
type b []int
var k = make([]b, 10, 5)
fmt.Println(k[8])
}
尝试运行时会出现以下错误。
panic: runtime error: makeslice: cap out of range
runtime.panic+0x9e /go/src/pkg/runtime/proc.c:1060
runtime.panic(0x453b00, 0x30020390) runtime.panicstring+0x94 /go/src/pkg/runtime/runtime.c:116
runtime.panicstring(0x4afd6c, 0x40d80c) runtime.makeslice+0x70 /go/src/pkg/runtime/slice.c:24
runtime.makeslice(0x44302c, 0xa, 0x0, 0x5, 0x0, ...) main.main+0x45 C:/GOEXCE~1/basics/DATATY~1/slice.go:8
main.main() runtime.mainstart+0xf 386/asm.s:93
runtime.mainstart() runtime.goexit /go/src/pkg/runtime/proc.c:178runtime.goexit()
----- goroutine created by -----
_rt0_386+0xbf 386/asm.s:80
我的问题是容量可以小于长度吗?
如果是'是',那么为什么会出现这个错误?
如果是'否',那么为什么这是一个运行时错误而不是编译时错误?
英文:
Made a slice where capacity is less than the length
package main
import "fmt"
func main() {
type b []int
var k = make([]b, 10, 5)
fmt.Println(k[8])
}
This when tried to run gives following error.
> panic: runtime error: makeslice: cap out of range
>
> runtime.panic+0x9e /go/src/pkg/runtime/proc.c:1060
>
> runtime.panic(0x453b00, 0x30020390) runtime.panicstring+0x94 /go/src/pkg/runtime/runtime.c:116
>
> runtime.panicstring(0x4afd6c, 0x40d80c) runtime.makeslice+0x70 /go/src/pkg/runtime/slice.c:24
>
> runtime.makeslice(0x44302c, 0xa, 0x0, 0x5, 0x0, ...) main.main+0x45 C:/GOEXCE~1/basics/DATATY~1/slice.go:8
>
> main.main() runtime.mainstart+0xf 386/asm.s:93
> runtime.mainstart() runtime.goexit /go/src/pkg/runtime/proc.c:178
>
> runtime.goexit()
>
> ----- goroutine created by -----
>
> _rt0_386+0xbf 386/asm.s:80
My question is can capacity be less than length?<br><br>
If 'Yes' then why this error came? <br>
And if 'No'then why this is a runtime error and why not a compile time?
答案1
得分: 19
不,容量不能小于长度。
切片是数组的一部分的引用。切片的容量表示其支持数组的大小。如果长度大于容量,那么它使用的是哪个内存?
对于切片s,以下不变式始终成立(除非你做了一些不安全的操作):
0 <= len(s) <= cap(s)
你的代码产生运行时错误而不是编译时错误,是因为错误不能总是在静态时检测到。在你的情况下可能可以,但考虑以下代码:
package main
import (
"fmt"
"rand"
)
func main() {
k := make([]int, rand.Int(), rand.Int())
fmt.Println(k)
}
传递给make的值直到运行时才能知道。
英文:
No, capacity cannot be less than length.
A slice is a reference to a part of an array. A slice's capacity represents the size of that backing array. If its length is greater than its capacity, then what memory is it using?
The following invariant always holds for a slice s (unless you've done something unsafe):
0 <= len(s) <= cap(s)
Your code produces a runtime error rather than a compile-time error because the error cannot always be detected statically. In your case it could be, but consider this code:
package main
import (
"fmt"
"rand"
)
func main() {
k := make([]int, rand.Int(), rand.Int())
fmt.Println(k)
}
The values passed to make cannot be known until runtime.
答案2
得分: 7
阅读Go编程语言规范。
> 长度和容量
>
> 切片的容量是底层数组中分配空间的元素数量。在任何时候,以下关系成立:
>
> 0 <= len(s) <= cap(s)
英文:
Read the Go Programming Language Specification.
> Length and capacity
>
> The capacity of a slice is the number of elements for which there is
> space allocated in the underlying array. At any time the following
> relationship holds:
>
> 0 <= len(s) <= cap(s)
答案3
得分: 0
检查长度和容量,如果长度小于0或长度大于容量,则会引发恐慌。
英文:
check the runtime/slice.go
func makeslice(et *_type, len, cap int) unsafe.Pointer {
mem, overflow := math.MulUintptr(et.size, uintptr(cap))
if overflow || mem > maxAlloc || len < 0 || len > cap {
// NOTE: Produce a 'len out of range' error instead of a
// 'cap out of range' error when someone does make([]T, bignumber).
// 'cap out of range' is true too, but since the cap is only being
// supplied implicitly, saying len is clearer.
// See golang.org/issue/4085.
mem, overflow := math.MulUintptr(et.size, uintptr(len))
if overflow || mem > maxAlloc || len < 0 {
panicmakeslicelen()
}
panicmakeslicecap()
}
return mallocgc(mem, et, true)
}
it will check the len and the cap, and give a panic if len<0 or len>cap.
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