英文:
How to find thee files with all extension based on file name regex in golang
问题
以下代码可以打开名为rx80_AWS.png的文件，但我想打开以rx80_AWS*开头的文件，不考虑扩展名，因为文件名将是唯一的，但我们在该文件夹中上传了.png、.pdf和.jpeg文件。
func DownloadCert(w http.ResponseWriter, r *http.Request) {
Openfile, err := os.Open("./certificate/rx80_AWS.png") // 打开要下载的文件
defer Openfile.Close() // 函数返回后关闭文件
fmt.Println("文件:", files)
if err != nil {
http.Error(w, "文件未找到。", 404) // 如果文件未找到，则返回404
return
}
tempBuffer := make([]byte, 512) // 创建一个字节数组以后面读取文件
Openfile.Read(tempBuffer) // 读取文件到字节数组
FileContentType := http.DetectContentType(tempBuffer) // 获取文件头
FileStat, _ := Openfile.Stat() // 获取文件信息
FileSize := strconv.FormatInt(FileStat.Size(), 10) // 将文件大小转换为字符串
Filename := attuid + "_" + skill
// 设置响应头
w.Header().Set("Content-Type", FileContentType+";"+Filename)
w.Header().Set("Content-Length", FileSize)
Openfile.Seek(0, 0) // 由于我们已经从文件中读取了512字节，所以将偏移量重置为0
io.Copy(w, Openfile) // 将文件复制到客户端
}
英文:
Below code can open file with name rx80_AWS.png but I want to open file with rx80_AWS* irrespective of the extension as the file names will be unique but we upload .png .pdf and .jpeg files in thee folder
func DownloadCert(w http.ResponseWriter, r *http.Request) {
Openfile, err := os.Open("./certificate/rx80_AWS.png") //Open the file to be downloaded later
defer Openfile.Close() //Close after function return
fmt.Println("FIle:", files)
if err != nil {
http.Error(w, "File not found.", 404) //return 404 if file is not found
return
}
tempBuffer := make([]byte, 512) //Create a byte array to read the file later
Openfile.Read(tempBuffer) //Read the file into byte
FileContentType := http.DetectContentType(tempBuffer) //Get file header
FileStat, _ := Openfile.Stat() //Get info from file
FileSize := strconv.FormatInt(FileStat.Size(), 10) //Get file size as a string
Filename := attuid + "_" + skill
//Set the headers
w.Header().Set("Content-Type", FileContentType+";"+Filename)
w.Header().Set("Content-Length", FileSize)
Openfile.Seek(0, 0) //We read 512 bytes from the file already so we reset the offset back to 0
io.Copy(w, Openfile) //'Copy' the file to the client
}
答案1
得分: 3
files, err := filepath.Glob("certificate/rx80_AWS*")
if err != nil {
// 处理错误
}
for _, filename := range files {
//...处理每个文件...
}
这里有一个在 playground 上运行的示例，通过匹配 /bin/*cat（匹配 cat、zcat 等）。
英文:
Use filepath.Glob.
files, err := filepath.Glob("certificate/rx80_AWS*")
if err != nil {
// handle errors
}
for _, filename in files {
//...handle each file...
}
Here is an example that works with the playground by matching /bin/*cat (matching cat, zcat, etc).
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