在一个字符串数组中找到最常见的元素。

huangapple go评论73阅读模式
英文:

Find the most common element in a string array GO

问题

我是你的中文翻译助手,以下是你要翻译的内容:

我对Go语言还比较新手,我在一个数组(Windrichting)中找不到最常见的字符串。应该是"N",但我的输出却是"W"(它总是给我最后一个字符串Windrichting[6])。有人可以帮忙吗?

这是我的代码:

package main

import "fmt"

func main() {
    Windrichting := [7]string{"N", "N", "N", "N", "O", "Z", "W"}

    windEL, winner := Mostcommon(Windrichting)

    fmt.Printf("Mostcommon windrichting: %s\n", windEL)
    fmt.Printf("Komt %d x voor\n", winner)
}

func Mostcommon(Windrichting [7]string) (windEL string, winner int) {
    var N int
    var O int
    var Z int
    var W int
    Windrichtingbase := [4]string{"N", "O", "Z", "W"}

    for _, v := range Windrichting {
        switch v {
        case Windrichtingbase[0]:
            N++
            if N > winner {
                winner = N
                windEL = "Noord"
            }
        case Windrichtingbase[1]:
            O++
            if O > winner {
                winner = O
                windEL = "Oost"
            }
        case Windrichtingbase[2]:
            Z++
            if Z > winner {
                winner = Z
                windEL = "Zuid"
            }
        case Windrichtingbase[3]:
            W++
            if W > winner {
                winner = W
                windEL = "West"
            }
        }
    }
    return windEL, winner
}

输出截图

英文:

i'm fairly new to golang and im having trouble finding the most common string in an array (Windrichting). it should be N but my output gives me W (it always gives me the last string so Windrichting[6]. Can someone help?

this is my code:

package main

import "fmt"

func main() {
	Windrichting := [7]string{"N", "N", "N", "N", "O", "Z", "W"}

windEL, winner := Mostcommon(Windrichting)

fmt.Printf("Mostcommon windrichting: %s\n", windEL)
fmt.Printf("Komt %d x voor\n", winner)
}


func Mostcommon(Windrichting [7]string) (windEL string, winner int) {
	var N int
	var O int
	var Z int
	var W int
	Windrichtingbase := [4]string{"N", "O", "Z", "W"}

for _, v := range Windrichting {
	switch v {
	case Windrichtingbase[0]:
		N++
		if N > winner {
			N = winner
			windEL = "Noord"
		}
	case Windrichtingbase[1]:
		O++
		if O > winner {
			O = winner
			windEL = "Oost"
		}
	case Windrichtingbase[2]:
		Z++
		if Z > winner {
			Z = winner
			windEL = "Zuid"
		}
	case Windrichtingbase[3]:
		W++
		if W > winner {
			W = winner
			windEL = "West"
		}
	}
}
return windEL, winner
}

output

答案1

得分: 1

赢家始终为0,你从未更新它。然后,在增加方向变量(N、O、Z和W)之后,你立即用存储在赢家中的零值覆盖它们。你需要改变赋值的顺序。

就像这个变化一样:https://go.dev/play/p/VaJgZcijFdh

还要注意,Go中的大写变量表示它们是可导出的。

英文:

winner is always 0 and you never update it. then after incrementing your direction variables (N, O, Z and W), you immediately overwrite them with the zero value stored in winner. You need to reverse the order of the assignment.

Like in this change: https://go.dev/play/p/VaJgZcijFdh

Note also, that capitalized variables in Go mean they're exported

答案2

得分: 0

这是一个替代实现。它使用直方图来收集单词出现的次数。然后通过直方图遍历来找到最常见的单词。没有硬编码。

https://go.dev/play/p/wTFvNaPRP6B

英文:

Here's an alternate implementation. It uses a histogram to collect the number of times a word appears. It then steps through the histogram to find the most common word. Nothing is hard-coded.

https://go.dev/play/p/wTFvNaPRP6B

huangapple
  • 本文由 发表于 2021年12月23日 07:15:02
  • 转载请务必保留本文链接:https://go.coder-hub.com/70456107.html
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