英文:
Go (GoLang) Gorilla/Mux Set Response Code
问题
我在尝试为Gorilla Mux中的路由设置响应代码时遇到了困难。如果我设置一个非常简单的路由，如下所示：
// dummy test route
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
fmt.Fprintf(w, `{"message":"OK"}`)
}).Methods("POST")
它似乎工作正常，并返回一个状态码为200，这是可以接受的，但是如果我尝试手动设置响应代码，如下所示：
// dummy test route
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.WriteHeader(http.StatusOK) // 添加了这个进行测试
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
fmt.Fprintf(w, `{"message":"OK"}`)
}).Methods("POST")
然后它似乎将响应代码设置为200，但在进行REST请求时仍然显示为错误：
POST *url*/test net::ERR_FAILED 200
我不确定为什么会这样，但这不是设置响应代码的正确方式吗？
英文:
I'm having difficulty while trying to set the Response Code for a Gorilla Mux Route in Go. If I have a very simple route set up as
// dummy test route
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
fmt.Fprintf(w, "{\"message\":\"OK\"}")
}).Methods("POST")
It seems to be working fine and returns a Status of 200 which is fine but if I try to set the response code manually like the below.
// dummy test route
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.WriteHeader(http.StatusOK) // added this to test
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
fmt.Fprintf(w, "{\"message\":\"OK\"}")
}).Methods("POST")
Then it seems to have set the response code to 200 but it still coming through as an error when making a REST request
POST *url*/test net::ERR_FAILED 200
I am not sure why this is but is this not the correct way to set a response code?
答案1
得分: 2
你必须将状态码写在最后，因为WriteHeader函数会将响应写入并刷新。
// 虚拟测试路由
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
w.WriteHeader(http.StatusOK) // 在设置完头部后，设置你的状态码
fmt.Fprintf(w, `{"message":"OK"}`)
}).Methods("POST")
英文:
You have to write the status code in the end as the WriteHeader function writes to the response and flushes it.
// dummy test route
router.HandleFunc("/test", func(w http.ResponseWriter, r *http.Request) {
w.Header().Set("Access-Control-Allow-Headers", "*")
w.Header().Set("Access-Control-Allow-Origin", "*")
w.Header().Set("Access-Control-Allow-Methods", "POST, GET")
w.Header().Set("Content-Type", "application/json")
w.WriteHeader(http.StatusOK) // Set your code here, after setting your headers
fmt.Fprintf(w, "{\"message\":\"OK\"}")
}).Methods("POST")
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