英文:
Compile Statically Linked GO Executable for use in AWS Lambda
问题
我正在尝试将一个Go程序（具体来说是Markus Kont的go-sigma-rule-engine）编译为可执行文件，以便我可以将其上传到AWS Lambda，并通过一个Python Lambda函数包含/执行它，该函数向规则引擎程序发出shell/os命令。
问题是，该程序依赖于许多依赖项，为了使其尽可能少出问题，我希望在上传到AWS Lambda之前静态链接并编译程序，以便所有必要的依赖项都包含在可执行文件本身中。
我的问题是，如何在Go中静态链接并编译程序，以便目标是AWS Lambda操作系统？
英文:
Context: I am trying to compile a Go program (Specifically, the go-sigma-rule-engine by Markus Kont) to an executable so that I can upload it to AWS Lambda (which is Amazon Linux 2 under the hood I believe, according to this post.) and include/execute it via a Python Lambda function that issues shell/os commands to the rule engine program.
Problem: This program relies on many dependencies and for it to work with as few issues as possible I would like to statically link the program and compile, before uploading to AWS Lambda, so that all necessary dependencies are included within the executable itself.
Question: How do I statically link then compile a program in Go such that I target the AWS Lambda OS?
答案1
得分: 1
这可以通过GOOS=linux go build .来完成。
Go默认会构建静态链接的可执行文件，只要正确地针对操作系统进行目标设置，你将获得一个在AWS Lambda上正常运行的二进制文件，而无需在部署包中包含任何特定的库。
英文:
This can be done via GOOS=linux go build .
Go builds statically linked executables by default so as long as the correct OS is targeted, you will get a binary that runs fine on AWS Lambda without having to include any specific libraries in the deployment package.
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