导入循环超过两个级别。

huangapple go评论74阅读模式
英文:

Import cycles more than two levels go

问题

所以我有一个需要解决的导入循环,并且我的项目结构基本上是这样的:

model.go -> procedure.go -> function.go

在我的函数中,我需要使用模型,并且我使用接口来处理它。目前我的代码基本上是这样的:

type imodel interface {
    foo()
}

type model struct {
}

func (m *model) run() {
    proc := &procedure{}
    proc.run(m)
}

func (m *model) foo() {
    //bla bla
}

type procedure struct {
}

func (p *procedure) run(model imodel) {
    funct := &function{}
    funct.run(model)
}

type function struct {
}

func (f *function) run(model imodel) {
    model.foo()
}

我的问题是,我是否应该像这样通过接口在每个类中传递我的模型,还是有其他的解决方法?

英文:

So i have this import cycle to solve, and my project structure basically likes this:

> model.go -> procedure.go -> function.go

In my function i need model and i use interface to handle it. Currently my code basically like this:

type imodel interface {
	foo()
}

type model struct {
}

func (m *model) run() {
	proc := &procedure{}
	proc.run(m)
}

func (m *model) foo() {
	//bla bla
}

type procedure struct {
}

func (p *procedure) run(model imodel) {
	funct := &function{}
	funct.run(model)
}

type function struct {
}

func (f *function) run(model imodel) {
	model.foo()
}

My question is should i pass my model using interface thorough every class like that or there's any other workaround?

答案1

得分: 3

我会将所有这些内容放在同一个包中。根据情况,我可能会将它们放在同一个包的不同文件中。

另外,你似乎没有导出imodel,所以它将是包内部的内容,除非你有多个具体的实现,否则你不需要一个接口。然后,"imodel"不是一个理想的名称,接口应该被命名为model,每个实现接口的具体类型应该根据其所模拟的内容进行命名。

英文:

I would put all of these in the same package. Depending on circumstances, I may put them in different files in the same package.

Also, you do not seem to export imodel, so it would be package-internal and unless you have multiple concrete implementations, you do not need an interface. Then, "imodel" is a less than ideal name, the interface should be named model and each concrete type implementing the interface should be named after what it models.

huangapple
  • 本文由 发表于 2021年12月1日 12:20:13
  • 转载请务必保留本文链接:https://go.coder-hub.com/70179088.html
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