如何在覆盖错误的同时追加函数结果?

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英文:

How do you append function result, while overwriting error?

问题

通常使用result, err := func()

当其中一个变量已经初始化时:

_, err := func()

var result string
result, err = func()

执行:

result, err = func()
all_results += result // 看起来多余和不必要

如何将结果附加到其中一个变量(result),并重置另一个变量?

// 类似于这样:
var result slice
// for 循环 {
result, _ += func() // 结合这一行
_, err = func() // 与这一行

你可以这样做吗:

result +=, err = func()
// 或者
result, err +=, = func()
// 或者
result, err += = func()
// 或者
result, err (+=, =) func() // ?
英文:

Usually, result, err := func() is used.

When one of the variables is already initialized:

_, err := func()

var result string
result, err = func()

Doing:

result, err = func()
all_results += result // seems redundant and unneeded

How do you append results to one of them (result), and reset the other one?

// along the lines of this:
var result slice
// for loop {
result, _ += func() // combine this line
_, err = func() // with this line

Can you do:

result +=, err = func()
// or
result, err +=, = func()
// or
result, err += = func()
// or
result, err (+=, =) func() // ?

答案1

得分: 2

语言规范不支持对多个返回值进行不同处理。

然而,可以通过一个辅助函数很容易实现:

func foo() (int, error) {
    return 1, nil
}

func main() {
    var all int

    add := func(result int, err error) error {
        all += result
        return err
    }

    if err := add(foo()); err != nil {
        panic(err)
    }
    if err := add(foo()); err != nil {
        panic(err)
    }
    if err := add(foo()); err != nil {
        panic(err)
    }
    fmt.Println(all)
}

这将输出 3(在 Go Playground 上尝试)。

如果你可以将错误处理移到辅助函数中,代码也可以这样写:

var all int

check := func(result int, err error) int {
    if err != nil {
        panic(err)
    }
    return result
}

all += check(foo())
all += check(foo())
all += check(foo())

fmt.Println(all)

这个输出结果相同,可以在 Go Playground 上尝试。

另一种变体是在辅助函数中完成所有操作:

var all int

handle := func(result int, err error) {
    if err != nil {
        panic(err)
    }
    all += result
}

handle(foo())
handle(foo())
handle(foo())

fmt.Println(all)

可以在 Go Playground 上尝试这个版本。

参考链接:https://stackoverflow.com/questions/28227095/multiple-values-in-single-value-context/28233172#28233172

英文:

The language spec does not support different treatment for multiple return values.

However, it's very easy to do it with a helper function:

func foo() (int, error) {
	return 1, nil
}

func main() {
	var all int

	add := func(result int, err error) error {
		all += result
		return err
	}

	if err := add(foo()); err != nil {
		panic(err)
	}
	if err := add(foo()); err != nil {
		panic(err)
	}
	if err := add(foo()); err != nil {
		panic(err)
	}
	fmt.Println(all)
}

This will output 3 (try it on the Go Playground).

If you can move the error handling into the helper function, it can also look like this:

var all int

check := func(result int, err error) int {
	if err != nil {
		panic(err)
	}
	return result
}

all += check(foo())
all += check(foo())
all += check(foo())

fmt.Println(all)

This outputs the same, try this one on the Go Playground.

Another variant can be to do everything in the helper function:

var all int

handle := func(result int, err error) {
	if err != nil {
		panic(err)
	}
	all += result
}

handle(foo())
handle(foo())
handle(foo())

fmt.Println(all)

Try this one on the Go Playground.

See related: https://stackoverflow.com/questions/28227095/multiple-values-in-single-value-context/28233172#28233172

huangapple
  • 本文由 发表于 2021年11月8日 01:32:10
  • 转载请务必保留本文链接:https://go.coder-hub.com/69874921.html
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