How to convert Date in Json to normal date to check if it is a leap year in GoLang?

I'm trying to convert the date in a json file to normal date in my .go script, i want to check if they are leap years or not, i already did this part, but i want to convert it to date, but i don't know how, i tried to use strconv.Itoa(users.Users[i].Date) but it didn't work !

Would appreciate any feedback or help, Thanks !

The error i received when i tried to add both types of date forms at the same time --> 2021/10/21 12:15:35 parsing time "1982/01/08" as "2006-01-02": cannot parse "/01/08" as "-"

BD.go

     package main
import (
"encoding/json"
"fmt"
"io/ioutil"
"log"
"os"
"time"
)
// Users struct which contains
// an array of users
type Users struct {
Users []User `json:"users"`
}
// User struct which contains a name
// a type and a list of social links
type User struct {
Firstname  string `json:"fname"`
Secondname string `json:"lname"`
Date       string `json:"date"`
}
func main() {
// Open our jsonFile
jsonFile, err := os.Open("users.json")
// if we os.Open returns an error then handle it
if err != nil {
fmt.Println(err)
}
fmt.Println("Successfully Opened users.json")
// defer the closing of our jsonFile so that we can parse it later on
defer jsonFile.Close()
// read our opened xmlFile as a byte array.
byteValue, _ := ioutil.ReadAll(jsonFile)
// we initialize our Users array
var users Users
// we unmarshal our byteArray which contains our
// jsonFile's content into 'users' which we defined above
json.Unmarshal(byteValue, &users)
// we iterate through every user within our users array and
// print out the user Type, their name, and their facebook url
// as just an example
// write a function to list out the people whose birthday is today.
// var yr int
for i := 0; i < len(users.Users); i++ {
date, err := time.Parse("2006/01/02", users.Users[i].Date)
if err != nil {
log.Fatal(err)
}
fmt.Println(date)
date1, err := time.Parse("2006-01-02", users.Users[i].Date)
if err != nil {
log.Fatal(err)
}
fmt.Println(date1)
// check if the date is a leap year, ex: 29 is not a leap year but 28th is !
if date.Day()%400 == 0 || (date.Day()%4 == 0 && date.Day()%100 != 0) {
fmt.Println("User First Name: " + users.Users[i].Firstname)
fmt.Println("User Second Name: " + users.Users[i].Secondname)
fmt.Println("User Date: " + users.Users[i].Date)
fmt.Println(users.Users[i].Date, " is a Leap Year ✨✨✨  ")
} else if date1.Day()%400 == 0 || (date1.Day()%4 == 0 && date1.Day()%100 != 0) {
fmt.Println("User First Name: " + users.Users[i].Firstname)
fmt.Println("User Second Name: " + users.Users[i].Secondname)
fmt.Println("User Date: " + users.Users[i].Date)
fmt.Println(users.Users[i].Date, " is a Leap Year ✨✨✨  ")
} else {
fmt.Println("User First Name: " + users.Users[i].Firstname)
fmt.Println("User Second Name: " + users.Users[i].Secondname)
fmt.Println("User Date: " + users.Users[i].Date)
fmt.Println(users.Users[i].Date, " is Not a Leap Year 💥💥💥 ")
}
}
}

.JSON file

{
"users": [
{
"Fname": "Johnny",
"Lname":"mane",
"date":"1982/01/08"
},
{
"Fname": "Wayne",
"Lname":"Bruce",
"date":"1965/01/30"
},
{
"Fname": "Gaga",
"Lname":"Lady",
"date":"1986/03/28"
},
{
"Fname": "radio",
"Lname":"head",
"date":"1988/02/29"
},
{
"Fname": "Mario",
"Lname":"torres",
"date":"1996/09/28"
},
{
"Fname": "robert",
"Lname":"Alex",
"date":"1991/12/01"
},
{
"Fname": "Julia",
"Lname":"sevak",
"date":"1991-03-07" -->
},
{
"Fname": "feb",
"Lname":"robert",
"date":"1995-01-31".  ---> 
}
]
}

If you unmarshal the date field into a string, you need to parse it with time.Parse using a given layout that matches your date format, e.g.:

date, err := time.Parse("2006/01/02", users.Users[i].Date)

Alternatively, you could unmarshal using json.UnmarshalJSON directly into a time.Time field, but you would need some additional code to support your custom date format as described in https://stackoverflow.com/questions/25087960/json-unmarshal-time-that-isnt-in-rfc-3339-format.

Download the araddon timeparse library from github

https://github.com/araddon/dateparse.git

Below is a sample to format date in golang with this amazing package without worrying about the string date

t, err := dateparse.ParseAny("3/1/2014")

You can then use the below function to format it.

 s:= t.Format("02 Jan 2006")

You can definitely try with the above package, it still has some corner cases but works for most of the cases.