英文:
How to convert Date in Json to normal date to check if it is a leap year in GoLang?
问题
我正在尝试将JSON文件中的日期转换为我的.go脚本中的普通日期，我想检查它们是否是闰年，我已经完成了这部分，但我想将其转换为日期，但我不知道如何操作，我尝试使用strconv.Itoa(users.Users[i].Date)，但它没有起作用！
如果有任何反馈或帮助，将不胜感激，谢谢！
当我尝试同时添加两种类型的日期格式时收到的错误消息为：2021/10/21 12:15:35 parsing time "1982/01/08" as "2006-01-02": cannot parse "/01/08" as "-"
以下是您提供的代码的翻译：
BD.go
package mainimport ("encoding/json""fmt""io/ioutil""log""os""time")// Users 结构体包含一个用户数组type Users struct {Users []User `json:"users"`}// User 结构体包含姓名、类型和社交链接列表type User struct {Firstname string `json:"fname"`Secondname string `json:"lname"`Date string `json:"date"`}func main() {// 打开json文件jsonFile, err := os.Open("users.json")// 如果os.Open返回错误，则处理错误if err != nil {fmt.Println(err)}fmt.Println("成功打开users.json")// 延迟关闭jsonFile，以便稍后解析defer jsonFile.Close()// 将打开的json文件读取为字节数组byteValue, _ := ioutil.ReadAll(jsonFile)// 初始化Users数组var users Users// 将包含json文件内容的byteArray解组为上面定义的'users'json.Unmarshal(byteValue, &users)// 遍历users数组中的每个用户，并打印出用户类型、姓名和Facebook链接作为示例// 编写一个函数来列出今天生日的人。// var yr intfor i := 0; i < len(users.Users); i++ {date, err := time.Parse("2006/01/02", users.Users[i].Date)if err != nil {log.Fatal(err)}fmt.Println(date)date1, err := time.Parse("2006-01-02", users.Users[i].Date)if err != nil {log.Fatal(err)}fmt.Println(date1)// 检查日期是否为闰年，例如：29不是闰年，但28是！if date.Day()%400 == 0 || (date.Day()%4 == 0 && date.Day()%100 != 0) {fmt.Println("用户名：", users.Users[i].Firstname)fmt.Println("用户姓氏：", users.Users[i].Secondname)fmt.Println("用户日期：", users.Users[i].Date)fmt.Println(users.Users[i].Date, "是闰年 ✨✨✨")} else if date1.Day()%400 == 0 || (date1.Day()%4 == 0 && date1.Day()%100 != 0) {fmt.Println("用户名：", users.Users[i].Firstname)fmt.Println("用户姓氏：", users.Users[i].Secondname)fmt.Println("用户日期：", users.Users[i].Date)fmt.Println(users.Users[i].Date, "是闰年 ✨✨✨")} else {fmt.Println("用户名：", users.Users[i].Firstname)fmt.Println("用户姓氏：", users.Users[i].Secondname)fmt.Println("用户日期：", users.Users[i].Date)fmt.Println(users.Users[i].Date, "不是闰年 💥💥💥")}}}
.JSON文件
{"users": [{"Fname": "Johnny","Lname":"mane","date":"1982/01/08"},{"Fname": "Wayne","Lname":"Bruce","date":"1965/01/30"},{"Fname": "Gaga","Lname":"Lady","date":"1986/03/28"},{"Fname": "radio","Lname":"head","date":"1988/02/29"},{"Fname": "Mario","Lname":"torres","date":"1996/09/28"},{"Fname": "robert","Lname":"Alex","date":"1991/12/01"},{"Fname": "Julia","Lname":"sevak","date":"1991-03-07"},{"Fname": "feb","Lname":"robert","date":"1995-01-31"}]}
希望对你有帮助！
英文:
I'm trying to convert the date in a json file to normal date in my .go script, i want to check if they are leap years or not, i already did this part, but i want to convert it to date, but i don't know how, i tried to use strconv.Itoa(users.Users[i].Date) but it didn't work !
Would appreciate any feedback or help, Thanks !
The error i received when i tried to add both types of date forms at the same time --> 2021/10/21 12:15:35 parsing time "1982/01/08" as "2006-01-02": cannot parse "/01/08" as "-"
BD.go
package mainimport ("encoding/json""fmt""io/ioutil""log""os""time")// Users struct which contains// an array of userstype Users struct {Users []User `json:"users"`}// User struct which contains a name// a type and a list of social linkstype User struct {Firstname string `json:"fname"`Secondname string `json:"lname"`Date string `json:"date"`}func main() {// Open our jsonFilejsonFile, err := os.Open("users.json")// if we os.Open returns an error then handle itif err != nil {fmt.Println(err)}fmt.Println("Successfully Opened users.json")// defer the closing of our jsonFile so that we can parse it later ondefer jsonFile.Close()// read our opened xmlFile as a byte array.byteValue, _ := ioutil.ReadAll(jsonFile)// we initialize our Users arrayvar users Users// we unmarshal our byteArray which contains our// jsonFile's content into 'users' which we defined abovejson.Unmarshal(byteValue, &users)// we iterate through every user within our users array and// print out the user Type, their name, and their facebook url// as just an example// write a function to list out the people whose birthday is today.// var yr intfor i := 0; i < len(users.Users); i++ {date, err := time.Parse("2006/01/02", users.Users[i].Date)if err != nil {log.Fatal(err)}fmt.Println(date)date1, err := time.Parse("2006-01-02", users.Users[i].Date)if err != nil {log.Fatal(err)}fmt.Println(date1)// check if the date is a leap year, ex: 29 is not a leap year but 28th is !if date.Day()%400 == 0 || (date.Day()%4 == 0 && date.Day()%100 != 0) {fmt.Println("User First Name: " + users.Users[i].Firstname)fmt.Println("User Second Name: " + users.Users[i].Secondname)fmt.Println("User Date: " + users.Users[i].Date)fmt.Println(users.Users[i].Date, " is a Leap Year ✨✨✨ ")} else if date1.Day()%400 == 0 || (date1.Day()%4 == 0 && date1.Day()%100 != 0) {fmt.Println("User First Name: " + users.Users[i].Firstname)fmt.Println("User Second Name: " + users.Users[i].Secondname)fmt.Println("User Date: " + users.Users[i].Date)fmt.Println(users.Users[i].Date, " is a Leap Year ✨✨✨ ")} else {fmt.Println("User First Name: " + users.Users[i].Firstname)fmt.Println("User Second Name: " + users.Users[i].Secondname)fmt.Println("User Date: " + users.Users[i].Date)fmt.Println(users.Users[i].Date, " is Not a Leap Year 💥💥💥 ")}}}
.JSON file
{"users": [{"Fname": "Johnny","Lname":"mane","date":"1982/01/08"},{"Fname": "Wayne","Lname":"Bruce","date":"1965/01/30"},{"Fname": "Gaga","Lname":"Lady","date":"1986/03/28"},{"Fname": "radio","Lname":"head","date":"1988/02/29"},{"Fname": "Mario","Lname":"torres","date":"1996/09/28"},{"Fname": "robert","Lname":"Alex","date":"1991/12/01"},{"Fname": "Julia","Lname":"sevak","date":"1991-03-07" -->},{"Fname": "feb","Lname":"robert","date":"1995-01-31". --->}]}
答案1
得分: 2
如果你将日期字段解组为字符串，你需要使用time.Parse函数解析它，使用与你的日期格式匹配的布局，例如：
date, err := time.Parse("2006/01/02", users.Users[i].Date)
或者，你可以直接使用json.UnmarshalJSON将其解组为time.Time字段，但是你需要一些额外的代码来支持你的自定义日期格式，如https://stackoverflow.com/questions/25087960/json-unmarshal-time-that-isnt-in-rfc-3339-format中所述。
英文:
If you unmarshal the date field into a string, you need to parse it with time.Parse using a given layout that matches your date format, e.g.:
date, err := time.Parse("2006/01/02", users.Users[i].Date)
Alternatively, you could unmarshal using json.UnmarshalJSON directly into a time.Time field, but you would need some additional code to support your custom date format as described in https://stackoverflow.com/questions/25087960/json-unmarshal-time-that-isnt-in-rfc-3339-format.
答案2
得分: 1
从GitHub上下载araddon timeparse库：
https://github.com/araddon/dateparse.git
以下是使用这个令人惊奇的包在golang中格式化日期的示例，无需担心字符串日期：
t, err := dateparse.ParseAny("3/1/2014")
然后可以使用以下函数进行格式化：
s := t.Format("02 Jan 2006")
你可以尝试使用上述包，它仍然存在一些特殊情况，但适用于大多数情况。
英文:
Download the araddon timeparse library from github
https://github.com/araddon/dateparse.git
Below is a sample to format date in golang with this amazing package without worrying about the string date
t, err := dateparse.ParseAny("3/1/2014")
You can then use the below function to format it.
s:= t.Format("02 Jan 2006")
You can definitely try with the above package, it still has some corner cases but works for most of the cases.
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