英文:
How to set slice interface values with reflection
问题
我想要构建一个函数,该函数接受一个通用指针数组,并根据MongoDB的结果填充该列表。
我不知道如何将从MongoDB获取的值设置到我的指针数组中。在下面的尝试中,程序会出现以下错误:reflect.Set: value of type []interface {} is not assignable to type []Person
当我打印出总数/找到的文档时,它与我期望的相符。所以我认为问题在于反射。
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
// 这里是我的MongoDB查询
var mongoResp struct {
Total int `bson:"total"`
Documents interface{} `bson:"documents"`
}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
receiverValue := reflect.ValueOf(receiver)
docs := []interface{}(mongoResp.Documents.(primitive.A))
receiverValue.Elem().Set(reflect.ValueOf(docs))
return mongoResp.Total, nil
}
type Person struct {
Name string `bson:"name"`
}
func main() {
var persons []Person
count, err := getListWithCount(context.Background(), &persons)
if err != nil {
log.Fatal(err)
}
fmt.Println(count)
fmt.Println(persons)
}
英文:
I would like to build a function that takes a generic pointer array and fill that list based on mongo results.
I don't know how to set the value I got from mongo into my pointer array. In the below attempt, program panics with following error : reflect.Set: value of type []interface {} is not assignable to type []Person
When I print total / documents found, it corresponds to what I am expecting. So I think question is about reflection.
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
//my mongo query here
var mongoResp struct {
Total int `bson:"total"`
Documents interface{} `bson:"documents"`
}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
receiverValue := reflect.ValueOf(receiver)
docs := []interface{}(mongoResp.Documents.(primitive.A))
receiverValue.Elem().Set(reflect.ValueOf(docs))
return mongoResp.Total, nil
}
type Person struct {
Name string `bson:"name"`
}
func main() {
var persons []Person
count, err := getListWithCount(context.Background(), &persons)
if err != nil {
log.Fatal(err)
}
fmt.Println(count)
fmt.Println(persons)
}
答案1
得分: 2
动态创建一个与查询文档匹配的结构类型。有关详细信息,请参见下面的注释。
func getListWithCount(receiver interface{}) (int, error) {
dst := reflect.ValueOf(receiver).Elem()
// 在这里添加你的mongo查询
// 创建一个与文档匹配的结构类型。
doct := reflect.StructOf([]reflect.StructField{
reflect.StructField{Name: "Total", Type: reflect.TypeOf(0), Tag: `bson:"total"`},
reflect.StructField{Name: "Documents", Type: dst.Type(), Tag: `bson:"documents"`},
})
// 解码为该类型的值。
docp := reflect.New(doct)
if err := cursor.Decode(docp.Interface()); err != nil {
return 0, err
}
docv := docp.Elem()
// 将Documents字段复制到*receiver。
dst.Set(docv.Field(1))
// 返回总数
return docv.Field(0).Interface().(int), nil
}
英文:
Dynamically create a struct type that matches the queried document. See commentary below for details.
func getListWithCount(receiver interface{}) (int, error) {
dst := reflect.ValueOf(receiver).Elem()
// Your mongo query here
// Create a struct type that matches the document.
doct := reflect.StructOf([]reflect.StructField{
reflect.StructField{Name: "Total", Type: reflect.TypeOf(0), Tag: `bson:"total"`},
reflect.StructField{Name: "Documents", Type: dst.Type(), Tag: `bson:"documents"`},
})
// Decode to a value of the type.
docp := reflect.New(doct)
if err := cursor.Decode(docp.Interface()); err != nil {
return 0, err
}
docv := docp.Elem()
// Copy the Documents field to *receiver.
dst.Set(docv.Field(1))
// Return the total
return docv.Field(0).Interface().(int), nil
}
答案2
得分: 2
你可以将bson.RawValue
解码为bson.RawValue
,然后将其解码为receiver
使用Unmarshal
。
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
// 这里是我的Mongo查询
var mongoResp struct {
Total int `bson:"total"`
Documents bson.RawValue `bson:"documents"`
}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
if err := mongoResp.Documents.Unmarshal(receiver); err != nil {
return 0, err
}
return mongoResp.Total, nil
}
你还可以将其实现为自定义的bson.Unmarshaler
。
type MongoResp struct {
Total int `bson:"total"`
Documents interface{} `bson:"documents"`
}
func (r *MongoResp) UnmarshalBSON(data []byte) error {
var temp struct {
Total int `bson:"total"`
Documents bson.RawValue `bson:"documents"`
}
if err := bson.Unmarshal(data, &temp); err != nil {
return err
}
r.Total = temp.Total
return temp.Documents.Unmarshal(r.Documents)
}
使用这种方式,你可以在函数中这样使用:
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
// 这里是我的Mongo查询
mongoResp := MongoResp{Documents: receiver}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
return mongoResp.Total, nil
}
英文:
You should be able to decode first into bson.RawValue
and then Unmarshal
it into the receiver
.
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
//my mongo query here
var mongoResp struct {
Total int `bson:"total"`
Documents bson.RawValue `bson:"documents"`
}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
if err := mongoResp.Documents.Unmarshal(receiver); err != nil {
return 0, err
}
return mongoResp.Total, nil
}
You can also implement it as a custom bson.Unmarshaler
.
type MongoResp struct {
Total int `bson:"total"`
Documents interface{} `bson:"documents"`
}
func (r *MongoResp) UnmarshalBSON(data []byte) error {
var temp struct {
Total int `bson:"total"`
Documents bson.RawValue `bson:"documents"`
}
if err := bson.Unmarshal(data, &temp); err != nil {
return err
}
r.Total = temp.Total
return temp.Documents.Unmarshal(r.Documents)
}
With that you would use it in the function like so:
func getListWithCount(ctx context.Context, receiver interface{}) (int, error) {
//my mongo query here
mongoResp := MongoResp{Documents: receiver}
if err := cursor.Decode(&mongoResp); err != nil {
return 0, err
}
return mongoResp.Total, nil
}
答案3
得分: -1
这里不需要使用reflect,你可以直接将其解码为你的Person切片。
func getPersons(ctx context.Context, coll *mongo.Collection, results interface{}) error {
cur, err := coll.Find(ctx, bson.D{})
if err != nil {
return err
}
err = cur.All(ctx, results)
if err != nil {
return err
}
return nil
}
而len
是结果的数量。
err = getPersons(ctx, coll, &persons)
require.NoError(t, err)
t.Logf("Got %d persons: %v", len(persons), persons)
请参考https://gist.github.com/xingyongtao/459f92490bdcbf7d5afe9f5d1ae6c04a。
英文:
there is no need to use reflect here, you can decode it directly to your Person slices
func getPersons(ctx context.Context, coll *mongo.Collection, results interface{}) error {
cur, err := coll.Find(ctx, bson.D{})
if err != nil {
return err
}
err = cur.All(ctx, results)
if err != nil {
return err
}
return nil
}
and the len
is the count of the results.
err = getPersons(ctx, coll, &persons)
require.NoError(t, err)
t.Logf("Got %d persons: %v", len(persons), persons)
see https://gist.github.com/xingyongtao/459f92490bdcbf7d5afe9f5d1ae6c04a
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