英文:
Return map of structs with testing expectations Go
问题
如何声明一个结构体的映射（map）？以下是firstFactorial_tests.go文件的代码示例：
package firstFactorial
import (
"testing"
"github.com/google/go-cmp/cmp"
)
func useCases() map[string]struct {
input int
want int
} {
tests := map[string]struct {
input int
want int
}{
"regular_number": {input: 3, want: 6},
"high_number": {input: 18, want: 6402373705728000},
"zero": {input: 0, want: 1},
"one": {input: 1, want: 1},
}
return tests
}
func TestRegular(t *testing.T) {
for name, tc := range useCases() {
t.Run(name, func(t *testing.T) {
got := firstFactorial(tc.input)
if diff := cmp.Diff(tc.want, got); diff != "" {
t.Fatalf("%s: expected: %v, got %v", name, tc.want, got)
}
})
}
}
func TestRecursive(t *testing.T) {
for name, tc := range useCases() {
t.Run(name, func(t *testing.T) {
got := firstFactorialRecursive(tc.input, 1)
if diff := cmp.Diff(tc.want, got); diff != "" {
t.Fatalf("%s: expected: %v, got %v", name, tc.want, got)
}
})
}
}
运行结果如下：
$ go test
# github.com/PZ01/coding-problems-go/firstFactorial
firstFactorial_test.go:10:11: expected type, found ':='
FAIL github.com/PZ01/coding-problems-go/firstFactorial [setup failed]
源文件如下：
package firstFactorial
func firstFactorial(num int) int {
factorial := 1
for num > 0 {
factorial *= num
num--
}
return factorial
}
func firstFactorialRecursive(num int, factorial int) int {
if num <= 0 {
return factorial
}
factorial *= num
num--
return firstFactorialRecursive(num, factorial)
}
另外，如果有关于如何使代码更紧凑的建议，我会很乐意提供帮助。
英文:
How do you declare a map of structs? The following firstFactorial_tests.go file:
package firstFactorial
import (
"testing"
"github.com/google/go-cmp/cmp"
)
func useCases() map[string]struct {
tests := map[string]struct {
input int
want int
}{
"regular_number": {input: 3, want: 6},
"high_number": {input: 18, want: 6.402373705728e+15},
"zero": {input: 0, want: 1},
"one": {input: 1, want: 1},
}
return tests
}
func TestRegular(t *testing.T) {
for name, tc := range useCases() {
t.Run(name, func(t *testing.T) {
got := firstFactorial(tc.input)
if diff := cmp.Diff(tc.want, got); diff != "" {
t.Fatalf("%s: expected: %v, got %v", name, tc.want, got)
}
})
}
}
func TestRecursive(t *testing.T) {
for name, tc := range useCases() {
t.Run(name, func(t *testing.T) {
got := firstFactorialRecursive(tc.input, 1)
if diff := cmp.Diff(tc.want, got); diff != "" {
t.Fatalf("%s: expected: %v, got %v", name, tc.want, got)
}
})
}
}
Returns the following:
$ go test
# github.com/PZ01/coding-problems-go/firstFactorial
firstFactorial_test.go:10:11: expected type, found ':='
FAIL github.com/PZ01/coding-problems-go/firstFactorial [setup failed]
Source file:
package firstFactorial
func firstFactorial(num int) int {
factorial := 1
for num > 0 {
factorial *= num
num--
}
return factorial
}
func firstFactorialRecursive(num int, factorial int) int {
if num <= 0 {
return factorial
}
factorial *= num
num--
return firstFactorialRecursive(num, factorial);
}
Also, any suggestion on making this more compact is appreciated.
Golang 1.7+
答案1
得分: 1
使用匿名结构体作为map值的定义。
func useCases() map[string]struct{ input, want int } {
return map[string]struct{ input, want int }{
"regular_number": {input: 3, want: 6},
"high_number": {input: 18, want: 6.402373705728e+15},
"zero": {input: 0, want: 1},
"one": {input: 1, want: 1},
}
}
英文:
Use a anonymous structs as map value definition.
func useCases() map[string]struct{ input, want int } {
return map[string]struct{ input, want int }{
"regular_number": {input: 3, want: 6},
"high_number": {input: 18, want: 6.402373705728e+15},
"zero": {input: 0, want: 1},
"one": {input: 1, want: 1},
}
}
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