如何设计goroutines程序来处理API限制错误

huangapple go评论76阅读模式
英文:

How to design goroutines program to handle api limit error

问题

刚开始学习关于goroutines的强大之处。

我有大约100个账户和10个地区,通过循环遍历它们,使用golang创建大约1000个goroutines来增加读取速度。它运行得太快了,以至于达到了每秒20次的API返回限制。

我该如何确保所有的goroutines都能以最大的调用速率(20/s)维持?我不确定哪种golang并发方法最适合一起处理错误。

例如:

func readInstance(acc string, region string, wg *sync.WaitGroup) {
    defer wg.Done()
    response, err := client.DescribeInstances(acc, region)
    if err != nil {
        log.Println(err) // API limit exceeding 20
        return
    }
    .
    .
    .
    .

}

func main() {
    accounts := []string{"g", "h", "i", ...}
    regions := []string{"g", "h", "i", ...}
    for _, region := range regions {
        for i := 0; i < len(accounts); i++ {
            wg.Add(1)
            go readInstance(accounts[i], region, &wg)
        }
    }
    wg.Wait()
}
英文:

Just started learning about the power of goroutines.

I have ~100 accounts and ~10 regions, looping through them to create ~ 1000 goroutines with golang to increase the reading speed. It worked too fast that it hit the API return limit of 20/ sec.

How do I ensure that all the goroutines can maintain at the maximum call rate of (20/s)? Im unsure of which golang concurrency methods works best together to handle the error.

eg:

func readInstance(acc string, region string, wg *sync.WaitGroup) {
    defer wg.Done()
    response, err := client.DescribeInstances(acc, region)
    if err != nil {
		log.Println(err) // API limit exceeding 20
		return
	}
    .
    .
    .
    .

}

func main() {
    accounts := []string{&quot;g&quot;, &quot;h&quot;, &quot;i&quot;, ...}
    regions := []string{&quot;g&quot;, &quot;h&quot;, &quot;i&quot;, ...}
	for _, region := range regions {
		for i := 0; i &lt; len(accounts); i++ {
			wg.Add(1)
			go readInstance(accounts[i], region, &amp;wg)
		}
	}
	wg.Wait()
}

答案1

得分: 3

如果您对在特定实际时间内可以进行的请求数量有一个固定的上限,您可以使用time.NewTicker()来间隔请求。

c := time.NewTicker(50 * time.Millisecond)
defer c.Stop()

现在,当您想要进行服务器请求时,只需在实际请求之前插入

<- c.C

即可。

英文:

If you have a fixed upper limit on how many requests you can do in a particular amount of real time, you can use a time.NewTicker() to space things out.

c := time.NewTicker(50 * time.Millisecond)
defer c.Stop()

Now, when you want to make a server request, just insert

&lt;- c.C

prior to the actual request.

答案2

得分: 0

我认为你可以尝试使用这个:https://github.com/uber-go/ratelimit

根据文档,它是并发安全的。

import (
	"fmt"
	"time"

	"go.uber.org/ratelimit"
)

func main() {
    rl := ratelimit.New(100) // 每秒限制100个请求

    prev := time.Now()
    for i := 0; i < 10; i++ {
        now := rl.Take()
        fmt.Println(i, now.Sub(prev))
        prev = now
    }

    // 输出:
    // 0 0
    // 1 10ms
    // 2 10ms
    // 3 10ms
    // 4 10ms
    // 5 10ms
    // 6 10ms
    // 7 10ms
    // 8 10ms
    // 9 10ms
}
英文:

i think you can try this: https://github.com/uber-go/ratelimit

According to the documentation, it is concurrency safe.

import (
	&quot;fmt&quot;
	&quot;time&quot;

	&quot;go.uber.org/ratelimit&quot;
)

func main() {
    rl := ratelimit.New(100) // per second

    prev := time.Now()
    for i := 0; i &lt; 10; i++ {
        now := rl.Take()
        fmt.Println(i, now.Sub(prev))
        prev = now
    }

    // Output:
    // 0 0
    // 1 10ms
    // 2 10ms
    // 3 10ms
    // 4 10ms
    // 5 10ms
    // 6 10ms
    // 7 10ms
    // 8 10ms
    // 9 10ms
}

huangapple
  • 本文由 发表于 2021年10月11日 12:34:11
  • 转载请务必保留本文链接:https://go.coder-hub.com/69521082.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定