英文:
How to decode hex to ASN.1 in golang
问题
我有一个以ASN.1 DER格式从HSM返回给我的ECDSA公钥。我需要创建一个与比特币兼容的33字节密钥。当我使用hex.EncodeToString(pubkey)打印密钥时，我得到以下输出：
3056301006072a8648ce3d020106052b8104000a034200049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
我在这里使用一个在线解码器：https://holtstrom.com/michael/tools/asn1decoder.php
它输出：
0x049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
然后，我可以使用hex.DecodeString(str)将其转换为所需的格式，以便将其输入到addrPubKey, err := btcutil.NewAddressPubKey(bs, &chaincfg.TestNet3Params)中。
请问如何在golang中解码以获取0x049...的输出？
谢谢。
英文:
I have an ECDSA public key that that is returned to me from an HSM in ASN.1 DER format. I need to create a bitcoin compatible key 33 byte. When I print out key in hex.EncodeToString(pubkey) I get the following output:
3056301006072a8648ce3d020106052b8104000a034200049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
I use an online decoder here: https://holtstrom.com/michael/tools/asn1decoder.php
And it outputs:
0x049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
I can then take that and hex.DecodeString(str) which gives me the necessary format to input this into addrPubKey, err := btcutil.NewAddressPubKey(bs, &chaincfg.TestNet3Params).
How do I decode this in golang to get the 0x049... output?
Thanks
答案1
得分: 0
我们首先需要使用标准库中的encoding/asn1包。
你只需要给go正确的结构体进行解码。从你的链接中我们可以看到有一个包含另一个SEQUENCE的SEQUENCE，其中包含两个OBJECTIDENTIFIER和一个BITSTRING。在go中，这将是：
type Ids struct {
OBi1 asn1.ObjectIdentifier
OBi2 asn1.ObjectIdentifier
}
type PubKey struct {
Id Ids
Bs asn1.BitString
}
现在我们只需要将数据解组到这个结构中：
str := `3056301006072a8648ce3d020106052b8104000a034200049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec`
bstring, err := hex.DecodeString(str)
if (err != nil) {
panic(err)
}
var decode PubKey
_, err = asn1.Unmarshal(bstring, &decode)
if (err != nil) {
panic(err)
}
fmt.Println(hex.EncodeToString(decode.Bs.Bytes))
请注意，你不需要将字符串编码为十六进制然后再解码，因为Unmarshall接受字节数组。
这将打印出预期的结果：
049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
再次说明，你可能不需要将其编码为字符串。
英文:
The first thing we need is to use the encoding/asn1 package from the standard library.
You only have to give go the right struct to decode into. From your link we can see that we have a SEQUENCE that contains another SEQUENCE with two OBJECTIDENTIFIER and a BITSTRING. In go this will be:
type Ids struct {
OBi1 asn1.ObjectIdentifier
OBi2 asn1.ObjectIdentifier
}
type PubKey struct {
Id Ids
Bs asn1.BitString
}
Now we only have to UnMarshall the data to this structure:
str := `3056301006072a8648ce3d020106052b8104000a034200049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec`
bstring, err := hex.DecodeString(str)
if (err != nil) {
panic(err)
}
var decode PubKey
_, err = asn1.Unmarshal(bstring, &decode)
if (err != nil) {
panic(err)
}
fmt.Println(hex.EncodeToString(decode.Bs.Bytes))
Note that you don't have to encode the string to hex and back again, since Unmarshall accepts a byte array
This will print the expected result:
049bb8e80670371f45508b5f8f59946a7c4dea4b3a23a036cf24c1f40993f4a1daad1716de8bd664ecb4596648d722a4685293de208c1d2da9361b9cba74c3d1ec
Once again you probably don't need to encode to string.
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