"net/url" can't parse url with pound

I have next code.

main.go:

package main

import "fmt"
import "net/url"

func main() {
    connString := "postgresql://postgres:password@192.168.1.10:5432/postgres"
    parsedUrl, err := url.Parse(connString)
    if err != nil {
        fmt.Println(err)
    }
    fmt.Println("=")
    fmt.Println(parsedUrl.User)
    fmt.Println("=")
}

Execution:

$ go run main.go
=
postgres:password
=

So far so good, you could see we successfully get parsedUrl.User as postgres:password. Problems happens when I change the password to password# which has a bound in it.

connString := "postgresql://postgres:password#@192.168.1.10:5432/postgres"

Then, run it again, it outputs as next:

=

=

You could see the code can't fetch postgres:password#. It looks # in html would be treat as anchor, is this the root cause?

To sum all, my question is: how I could fix my code to handle the situation which I have # in password?

Yes, # indicates a fragment.

A way to solve it would be to escape the # character:

connString := fmt.Sprintf("postgresql://postgres:password%s@192.168.1.10:5432/postgres", url.PathEscape("#"))

parsedUrl, _ := url.Parse(connString)

fmt.Println(url.PathUnescape(parsedUrl.User.String()))

And the output:

postgres:password# <nil>

You can use url.QueryEscape()

Example

package main

import (
	"fmt"
	"net/url"
)

func main() {
	connString := `postgresql://postgres:` + url.QueryEscape(`password#`) + `@192.168.1.10:5432/postgres`
	xurl, err := url.Parse(connString)
	if err != nil {
		fmt.Println(err)
	}
	fmt.Println("=")

	fmt.Println(xurl.User.Username())
	fmt.Println(xurl.User.Password())
	fmt.Println("=")
}