Exclusive locking in Go

How can a file be opened such that only one process can write to it at a time in Golang?

I am new to Golang and was trying to learn it by writing something. Was attempting to create a secret storage tool which stores, say, api keys to a file; during which I came across an issue - if two instance of same program runs together (hypothetically) a race condition can occur and damage the file.

So, I was checking for a way to lock the file so that only one process can write to it at a time. Reading simultaneously is ok.

Found this answer : https://stackoverflow.com/questions/52986413/how-to-get-an-exclusive-lock-on-a-file-in-go on stackoverflow. but in the comments of the same, it's mentioned

> your package uses flock() for locking on Unix so doesn't provide OS level mandatory locking

Tried os.ModeExclusive.

f, err := os.OpenFile(".secrets", os.O_RDWR|os.O_CREATE, os.ModeExclusive)

But it prevents the file from accessing the next time program runs. Can you please explain what this mode does. Not able to understand it from the docs.

Also tried:

f, err := os.OpenFile(".secrets", os.O_RDWR|os.O_CREATE, 0744)

On using the above, anyone can read/write when the file is opened.

I'll try to explain the os.ModeExclusive bit of your question:

> Tried os.ModeExclusive.
>
> f, err := os.OpenFile(".secrets", os.O_RDWR|os.O_CREATE, os.ModeExclusive)
>
> But it prevents the file from accessing the next time program runs.
> Can you please explain what this mode does. Not able to understand it
> from the docs.

OpenFile() with os.ModeExclusive basically creates a file where not even the file owner has read and write permissions on it (at least this is the behavior I observed on unix). that is why it "doesn't work" the next time when it tries to open the file again:

$ cat prog.go
package main
import (
        "fmt"
        "log"
        "os"
)
func main() {
        f, err := os.OpenFile(".secrets", os.O_RDWR|os.O_CREATE, os.ModeExclusive)
        if err != nil {
                log.Fatal(err)
        }
        defer f.Close()
        fmt.Fprintf(f, "this is my secret\n")
}
$ go build prog.go
$ ./prog
$ ls -al
total 2.1M
drwxr-xr-x 2 marco marco 4.0K Aug 28 13:53 ./
drwxr-xr-x 4 marco marco 4.0K Aug 28 13:22 ../
-rwxr-xr-x 1 marco marco 2.1M Aug 28 13:53 prog*
-rw-r--r-- 1 marco marco  230 Aug 28 13:49 prog.go
---------- 1 marco marco   17 Aug 28 13:53 .secrets    <-- HERE IT IS
$ ./prog
2021/08/28 13:54:27 open .secrets: permission denied
$ cat .secrets
cat: .secrets: Permission denied
$ chmod u+rw .secrets
$ cat .secrets
this is my secret
$

os.ModeExclusive can also be used with Chmod() of course on already existing files.

> The convention (at least for the standard library) is the following: No function/method is safe for concurrent use unless explicitly stated (or obvious from the context).
> It is not safe to write concurrently to an os.File via Write() without external synchronization.

source: https://stackoverflow.com/a/30746629/13067552

You can use RMutex from sync package to avoid data race. *sync.RWMutex

package main
import (
	"fmt"
	"os"
	"sync"
)
type MyFile struct {
	l    *sync.RWMutex
	file *os.File
}
func (f *MyFile) Write(b []byte) (int, error) {
	f.l.Lock()
	defer f.l.Unlock()
	return f.file.Write(b)
}
func (f *MyFile) Read(b []byte) (int, error) {
	f.l.RLock()
	defer f.l.RUnlock()
	return f.file.Read(b)
}
func main() {
	f, err := os.Open("tmp")
	if err != nil {
		// handle here
	}
	defer f.Close()
	myfile := &MyFile{
		l:    &sync.RWMutex{},
		file: f,
	}
	myfile.Write([]byte("secret"))
	b1 := make([]byte, 5)
	myfile.Read(b1)
	fmt.Println(string(b1))
}