如何在定义嵌套映射时避免重复？

huangapple
go评论125阅读模式
英文:

How to avoid repetition when defining this nested map

问题

你可以使用结构体来定义map[string]string，然后在properties中引用该结构体。这样你就不需要每次都定义map[string]string了。以下是修改后的代码示例：

  1. type StringMap map[string]string
  3. var deviceSchemaJson = map[string]interface{}{
  4. 	"additionalProperties": false,
  5. 	"properties": map[string]interface{}{
  6. 		"application": StringMap{
  7. 			"type": "string",
  8. 		},
  9. 		"hostname": StringMap{
  10. 			"type": "string",
  11. 		},
  12. 		"ipaddress": map[string]interface{}{
  13. 			"oneOf": []map[string]string{{"format": "ipv4"}, {"format": "ipv6"}},
  14. 			"type":  "string",
  15. 		},
  16. 		"kernel_version": StringMap{
  17. 			"type": "string",
  18. 		},
  19. 	},
  20. 	"type": "object",
  21. }

通过定义StringMap结构体，你可以在properties中直接使用StringMap类型，避免了每次都定义map[string]string的麻烦。

英文:

In one of my json schema, I have a map like this

  1. var deviceSchemaJson = map[string]interface{}{
  2. 	"additionalProperties": false,
  3. 	"properties": map[string]interface{}{
  4. 		"application": map[string]string{
  5. 			"type": "string",
  6. 		},
  7. 		"hostname": map[string]string{
  8. 			"type": "string",
  9. 		},
  10. 		"ipaddress": map[string]interface{}{
  11. 			"oneOf": []map[string]string{{"format": "ipv4"},{"format": "ipv6"}},
  12. 			"type": "string",
  13. 		},
  14. 		"kernel_version": map[string]string{
  15. 			"type": "string",
  16. 		},
  17. 	},
  18. 	"type": "object",
  19. }

How can I avoid defining map[string]string every time?

答案1

得分: 2

如果你更喜欢这个版本，可以尝试一下：

  1. package main
  3. import (
  4. 	"fmt"
  5. )
  7. func main() {
  8. 	fmt.Printf("%#v\n", deviceSchemaJson)
  9. }
  11. var deviceSchemaJson = value{
  12. 	"additionalProperties": false,
  13. 	"properties": value{
  14. 		"application": value{
  15. 			"type": "string",
  16. 		},
  17. 		"hostname": value{
  18. 			"type": "string",
  19. 		},
  20. 		"ipaddress": value{
  21. 			"oneOf": []valuestring{{"format": "ipv4"}, {"format": "ipv6"}},
  22. 			"type":  "string",
  23. 		},
  24. 		"kernel_version": valuestring{
  25. 			"type": "string",
  26. 		},
  27. 	},
  28. 	"type": "object",
  29. }
  31. type value map[string]interface{}
  33. type valuestring map[string]string

链接：https://play.golang.org/p/6Kq5pvXYvNm

英文:

try this if that suites you better

  1. package main
  3. import (
  4. 	"fmt"
  5. )
  7. func main() {
  8. 	fmt.Printf("%#v\n",deviceSchemaJson)
  9. }
  11. var deviceSchemaJson = value{
  12. 	"additionalProperties": false,
  13. 	"properties": value{
  14. 		"application": value{
  15. 			"type": "string",
  16. 		},
  17. 		"hostname": value{
  18. 			"type": "string",
  19. 		},
  20. 		"ipaddress": value{
  21. 			"oneOf": []valuestring{{"format": "ipv4"}, {"format": "ipv6"}},
  22. 			"type":  "string",
  23. 		},
  24. 		"kernel_version": valuestring{
  25. 			"type": "string",
  26. 		},
  27. 	},
  28. 	"type": "object",
  29. }
  31. type value map[string]interface{}
  33. type valuestring map[string]string

https://play.golang.org/p/6Kq5pvXYvNm

答案2

得分: 0

如何避免每次都定义map[string]string？

通过定义表示数据结构的类型。

  1. type DeviceSchema struct {
  2. 	AdditionalProperties bool
  3. 	Properties Properties
  4. 	Type string
  5. }
  7. type Properties struct {
  8. 	Application string
  9. 	Hostname string
  10. 	IpAddress []map[string]string
  11. 	KernelVersion string
  12. }
  14. func main() {
  15. 	deviceSchemaData := DeviceSchema{
  16. 		AdditionalProperties: false,
  17. 		Properties: Properties{
  18. 			IpAddress: []map[string]string{{"format": "ipv4"},{"format": "ipv6"}},
  19. 		},
  20. 		Type: "object",
  21. 	}
  22. 	fmt.Println(deviceSchemaData)
  23. }

链接：https://play.golang.org/p/iHfoft1zyAn

英文:

> How can I avoid defining map[string]string every time?

By defining types which represent your data structure.

  1. type DeviceSchema struct {
  2. 	AdditionalProperties bool
  3. 	Properties Properties
  4. 	Type string
  5. }
  7. type Properties struct {
  8. 	Application string
  9. 	Hostname string
  10. 	IpAddress []map[string]string
  11. 	KernelVersion string
  12. }
  14. func main() {
  15. 	deviceSchemaData := DeviceSchema{
  16. 		AdditionalProperties: false,
  17. 		Properties: Properties{
  18. 			IpAddress: []map[string]string{{"format": "ipv4"},{"format": "ipv6"}},
  19. 		},
  20. 		Type: "object",
  21. 	}
  22. 	fmt.Println(deviceSchemaData)
  23. }

https://play.golang.org/p/iHfoft1zyAn

答案3

得分: 0

简化定义的一种方法是：

  1. func stringMap(s...string) map[string]string {
  2.   ret:=map[string]string{}
  3.   for i:=0; i<len(s);i+=2 {
  4.      ret[s[i]]=s[i+1]
  5.   }
  6.   return ret
  7. }
  9. var deviceSchemaJson = map[string]interface{}{
  10.     "additionalProperties": false,
  11.     "properties": map[string]interface{}{
  12.         "application": stringMap("type","string"),
  13.         "hostname": stringMap("type","string"),
  14.         "ipaddress": map[string]interface{}{
  15.             "oneOf": []map[string]string{stringMap("format","ipv4"),stringMap("format","ipv6")},
  16.             "type": "string",
  17.         },
  18.         "kernel_version": stringMap("type","string"),
  19.     },
  20.     "type": "object",
  21. }
英文:

One way to simplify the definition would be:

  1. func stringMap(s...string) map[string]string {
  2.   ret:=map[string]string{}
  3.   for i:=0; i&lt;len(s);i+=2 {
  4.      ret
    展开收缩
    ]=s[i+1]
  5.   }
  6.   return ret
  7. }
  9. var deviceSchemaJson = map[string]interface{}{
  10.     &quot;additionalProperties&quot;: false,
  11.     &quot;properties&quot;: map[string]interface{}{
  12.         &quot;application&quot;: stringMap(&quot;type&quot;,&quot;string&quot;),
  13.         &quot;hostname&quot;: stringMap(&quot;type&quot;,&quot;string&quot;),
  14.         &quot;ipaddress&quot;: map[string]interface{}{
  15.             &quot;oneOf&quot;: []map[string]string{stringMap(&quot;format&quot;,&quot;ipv4&quot;),stringMap(&quot;format&quot;,&quot;ipv6&quot;)},
  16.             &quot;type&quot;: &quot;string&quot;,
  17.         },
  18.         &quot;kernel_version&quot;: stringMap(&quot;type&quot;,&quot;string&quot;),
  19.     },
  20.     &quot;type&quot;: &quot;object&quot;,
  21. }
  23. </details>

huangapple
  • 本文由 发表于 2021年8月23日 03:57:53
  • 转载请务必保留本文链接：https://go.coder-hub.com/68884721.html
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