Question about indexing characters of strings

Below is the program I created to understand how indexing of string characters work in Go:

package main
import "fmt"
func main() {
	vendor1 := "Cisco"
	fmt.Println(vendor1[0])  
	fmt.Println(vendor1[1:4]) 
	fmt.Println(vendor1[1:])  
	fmt.Println(vendor1[:])
}

Output:

C:\Golang\VARIABLE> go run .\variable.go
67
isc
isco
Cisco

What puzzled me is that Println(vendor1[0]) returns the number '67' instead of 'C', why is that so? Why it is different from Println(vendor1[1:4]) , Println(vendor1[1:]) and Println(vendor1[:]) which all return the desired characters?

Index expressions are not the same thing as slice expressions, don't conflate them.

Indexing, as opposed to slicing, returns a byte which is a type alias of uint8, and Println simply prints out the unsigned integer.

Slicing returns a string, which is why Println outputs a text.

To print the value at index 0 use fmt.Printf("%c\n", vendor1[0]) instead of fmt.Println(vendor1[0]),for the other three values you can use %s with fmt.Printf() since they are string.I modified your code as follows:

package main
import (
	"fmt"
)
func main() {
	vendor1 := "Cisco"
	fmt.Printf("%c\n", vendor1[0])
	fmt.Printf("%s\n", vendor1[1:4])
	fmt.Printf("%s\n", vendor1[1:])
	fmt.Printf("%s\n", vendor1[:])
}

Output:

C
isc
isco
Cisco