当在switch case中出现错误时,如何使switch语句正常工作?

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英文:

How do I get the switch statement to work when there is an error in switch case

问题

根据用户从命令行输入的内容,switch case 语句根据一个整数返回评级。由于命令行参数的类型是字符串,我首先将其转换为 int,然后在 switch 语句中使用。

package main

import (
	"fmt"
	"os"
	"reflect"
	"strconv"
)

func main() {
	rating, _ := strconv.Atoi(os.Args[1])
	fmt.Println(reflect.TypeOf(rating))
	switch {
	case rating >= 2100:
		fmt.Println("grand master")
	case rating >= 1900:
		fmt.Println("candidate master")
	case rating >= 1600:
		fmt.Println("expert")
	case rating >= 1400:
		fmt.Println("pupil")
	case rating < 1400:
		fmt.Println("newbie")
	}
}

现在在 rating >= 2100 和其他所有比较中都存在错误。错误信息如下:

cannot convert rating >= 2100 (untyped bool value) to intcompilerInvalidUntypedConversion

我无法理解如何解决这个问题。

请帮忙解决!

英文:

based on user input from command line, switch case returns rating for an integer. Since command line arguments are of type string, I first convert it to int and then use it in switch.

package main

import (
  &quot;fmt&quot;
  &quot;os&quot;
  &quot;reflect&quot;
  &quot;strconv&quot;
)

func main() {
 rating, _ := strconv.Atoi(os.Args[1])
 fmt.Println(reflect.TypeOf(rating))
 switch rating {
  case rating &gt;= 2100:
	fmt.Println(&quot;grand master&quot;)
  case rating &gt;= 1900:
	fmt.Println(&quot;candidate master&quot;)
  case rating &gt;= 1600:
	fmt.Println(&quot;expert&quot;)
  case rating &gt;= 1400:
	fmt.Println(&quot;pupil&quot;)
  case rating &lt; 1400:
	fmt.Println(&quot;newbie&quot;)
  }

}

Now there is error on rating >= 2100, for all comparisons rather. It goes as follows:

cannot convert rating &gt;= 2100 (untyped bool value) to intcompilerInvalidUntypedConversion

Not able to understand how to resolve this.

Please help!

答案1

得分: 6

如果你使用switch表达式,你必须在可比较的地方使用case表达式。规范:Switch语句:

对于每个(可能转换的)case表达式x和switch表达式的值tx == t必须是一个有效的比较

也就是说,如果你使用switch rating { ... },那么你只需要指定整数值,例如2100,而不是像rating >= 2100这样的比较。

显然,你不想要单个值,而是范围,所以省略switch表达式:

switch {
case rating >= 2100:
    fmt.Println("grand master")
case rating >= 1900:
    fmt.Println("candidate master")
case rating >= 1600:
    fmt.Println("expert")
case rating >= 1400:
    fmt.Println("pupil")
case rating < 1400:
    fmt.Println("newbie")
}
英文:

If you use a switch expression, you have to use case expressions where they are comparable. Spec: Switch statements:

> For each (possibly converted) case expression x and the value t of the switch expression, x == t must be a valid comparison.

That is, if you use switch rating { ... }, then you only need to specify the integer values, e.g. 2100, and not a comparison like rating &gt;= 2100.

Obviously you don't want single values but ranges, so omit the switch expression:

switch {
case rating &gt;= 2100:
	fmt.Println(&quot;grand master&quot;)
case rating &gt;= 1900:
	fmt.Println(&quot;candidate master&quot;)
case rating &gt;= 1600:
	fmt.Println(&quot;expert&quot;)
case rating &gt;= 1400:
	fmt.Println(&quot;pupil&quot;)
case rating &lt; 1400:
	fmt.Println(&quot;newbie&quot;)
}

答案2

得分: 0

你只是在重复已经存在于上方的变量名。

英文:

you're basically repeating the variable name that already exists aboveenter image description here

huangapple
  • 本文由 发表于 2021年8月16日 20:14:33
  • 转载请务必保留本文链接:https://go.coder-hub.com/68802626.html
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