英文:
How to add data in a nested map?
问题
我有一个嵌套的映射数据，其中一个是列表，我想使用append方法向列表中添加数据，但是返回了一个错误：
invalid argument: baseData["a"].(map[string]interface{})["actions"] (map index expression of type interface{}) is not a slice
以下是你的代码：
baseData := map[string]interface{}{}dateData := map[string]interface{}{"date": map[string]interface{}{"updatedAt": "yyyy-mm-dd","isChanged": true,},"actions": []interface{}{},}baseData["a"] = dateData.....示例{"a": {"actions": [],"date": {"isChanged": true,"updatedAt": "yyyy-mm-dd"}},"b": {"actions": [],"date": {"isChanged": true,"updatedAt": "yyyy-mm-dd"}}}我的代码：actionData := map[string]interface{}{"id": data.Id,"action": data.Action,}baseData["a"].(map[string]interface{})["actions"] = append(baseData["a"].(map[string]interface{})["actions"], actionData)
希望这可以帮助到你！
英文:
I have a nested map data that
One of them is a list, and I want to add data to the list using the append method
but it return an error :
invalid argument: baseData["a"].(map[string]interface{})["actions"] (map index expression of type interface{}) is not a slice
baseData := map[string]interface{}{}dateData := map[string]interface{}{"date": map[string]interface{}{"updatedAt": "yyyy-mm-dd","isChanged": true,},"actions": []interface{}{},}baseData["a"] = dateData.....example{"a": {"actions": [],"date": {"isChanged": true,"updatedAt": "yyyy-mm-dd"}},"b": {"actions": [],"date": {"isChanged": true,"updatedAt": "yyyy-mm-dd"}}
}
My codes
actionData := map[string]interface{}{"id": data.Id,"action": data.Action,}baseData["a"].(map[string]interface{})["actions"] = append(baseData["a"].(map[string]interface{})["actions"], actionData)
答案1
得分: 1
做这个：
package mainimport "fmt"func main() {dateData := map[string]interface{}{"actions": []interface{}{},}dateData["actions"] = append(dateData["actions"].([]interface{}), "foobar")fmt.Printf("%+v\n", dateData)}
输出：
map[actions:[foobar]]
英文:
Do this:
package mainimport "fmt"func main() {dateData := map[string]interface{}{"actions": []interface{}{},}dateData["actions"] = append(dateData["actions"].([]interface{}), "foobar")fmt.Printf("%+v\n", dateData)}
Output:
map[actions:[foobar]]
答案2
得分: 0
baseData := map[string]interface{}{}
dateData := map[string]interface{}{
"date": map[string]interface{}{
"updatedAt": "yyyy-mm-dd",
"isChanged": true,
},
"actions": []interface{}{},
}
baseData["a"] = dateData
actionData := map[string]interface{}{
"id": data.Id,
"action": data.Action,
}
baseData["a"].(map[string]interface{})["actions"] = append(baseData["a"].(map[string]interface{})["actions"].([]interface{}), actionData)
英文:
baseData := map[string]interface{}{}dateData := map[string]interface{}{"date": map[string]interface{}{"updatedAt": "yyyy-mm-dd","isChanged": true,},"actions": []interface{}{},}baseData["a"] = dateDataactionData := map[string]interface{}{"id": data.Id,"action": data.Action,}baseData["a"].(map[string]interface{})["actions"] = append(baseData["a"].(map[string]interface{})["actions"].([]interface{}), actionData)
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