英文:
Get streamed file size from grpc server interceptor
问题
在这种拦截器中,你可以通过grpc.ServerStream参数(ss)来获取传入文件的大小。具体来说,你可以使用ss.RecvMsg方法来接收FileForm消息,并通过获取Upfile1、Upfile2和Upfile3字段的长度来计算文件的大小。以下是一个示例代码片段,展示了如何在拦截器中获取传入文件的大小:
func logInterceptor(srv interface{}, ss grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
fmt.Println("Log Interceptor")
// 接收FileForm消息
fileForm := &pdfcompose.FileForm{}
err := ss.RecvMsg(fileForm)
if err != nil {
return err
}
// 计算文件大小
fileSize := len(fileForm.Upfile1) + len(fileForm.Upfile2) + len(fileForm.Upfile3)
fmt.Println("File size:", fileSize)
// 继续处理请求
err = handler(srv, ss)
if err != nil {
return err
}
return nil
}
在这个示例中,我们首先创建一个FileForm实例,然后使用ss.RecvMsg方法将接收到的消息存储到FileForm实例中。接下来,我们计算Upfile1、Upfile2和Upfile3字段的长度,并将它们相加得到文件的大小。最后,我们打印文件大小,并继续处理请求。
请注意,这只是一个示例代码片段,你可能需要根据你的实际情况进行适当的修改和调整。
英文:
I have a Go server bidirectional stream method defined like this in proto-file:
syntax = "proto3";
option go_package="pdfcompose/;pdfcompose";
package pdfcompose;
service PdfCompose {
rpc Send (stream FileForm) returns (stream PdfFile) {}
}
message FileForm {
bytes Upfile1 = 1;
bytes Upfile2 = 2;
bytes Upfile3 = 3;
}
message PdfFile {
bytes File = 1;
}
And my log interceptor has the following interface:
func logInterceptor(srv interface{}, ss grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
fmt.Println("Log Interceptor")
err := handler(srv, ss)
if err != nil {
return err
}
return nil
}
And I'm using https://github.com/grpc-ecosystem/go-grpc-middleware as an interceptor engine.
I need to implement logging of the streaming file size (for educational purposes) and trying to find out where I can get any data about FileForm and it contents.
My first guess was to look into grpc.ServerStream argument (ss) to find something about it and it looks like it contains a lot of data like max and min MessageSize, but noting about actual content length.
How I can get size of incoming file with this kind of interceptors?
答案1
得分: 0
所以,正如@Brits在上面提到的,实现我想要的工作方式是编写流的包装器。
这是一个示例:https://github.com/grpc-ecosystem/go-grpc-middleware/blob/master/validator/validator.go 我从这个存储库中获取了以下代码,并且我希望我正确理解了Apache 2.0许可证,并且复制了这部分代码没有问题:
// StreamServerInterceptor返回一个新的流服务器拦截器,用于验证传入的消息。
//
// 无效的消息将在RPC的类型上拒绝InvalidArgument
之前发生。对于ServerStream
(1:m)请求,它将在到达任何用户空间处理程序之前发生。对于ClientStream
(n:1)或BidiStream
(n:m)RPC,消息将在调用stream.Recv()
时被拒绝。
func StreamServerInterceptor() grpc.StreamServerInterceptor {
return func(srv interface{}, stream grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
wrapper := &recvWrapper{stream}
return handler(srv, wrapper)
}
}
type recvWrapper struct {
grpc.ServerStream
}
func (s *recvWrapper) RecvMsg(m interface{}) error {
if err := s.ServerStream.RecvMsg(m); err != nil {
return err
}
if err := validate(m); err != nil {
return err
}
return nil
}
validate()
函数实际上将请求作为interface{}
获取,并且您需要使用类型断言将此请求转换为所需的类型,如v := req.(type)
。
例如,我将请求类型定义为FileForm
,并能够检查其内容:
func logFileSize(req interface{}) error {
m := req.(*pdfcompose.FileForm)
println("SizeOfUpfile1: " + strconv.Itoa(int(binary.Size(m.Upfile1))))
if m.Upfile2 != nil {
println("SizeOfUpfile2: " + strconv.Itoa(int(binary.Size(m.Upfile3))))
}
if m.Upfile3 != nil {
println("SizeOfUpfile2: " + strconv.Itoa(int(binary.Size(m.Upfile3))))
}
return nil
}
func (s *recvWrapper) RecvMsg(m interface{}) error {
if err := s.ServerStream.RecvMsg(m); err != nil {
return err
}
//z := m.(pdfcompose.FileForm)
if err := logFileSize(m); err != nil {
return err
}
return nil
}
func StreamServerInterceptor() grpc.StreamServerInterceptor {
return func(srv interface{}, stream grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
wrapper := &recvWrapper{stream}
return handler(srv, wrapper)
}
}
英文:
So, as @Brits has mentioned above, the working way to implement what I wanted is to write wrapper for stream.
Here is an example: https://github.com/grpc-ecosystem/go-grpc-middleware/blob/master/validator/validator.go I took the following code from this repo and I hope I understand apache2 license correct and there is no issues with copying a part of this code:
// StreamServerInterceptor returns a new streaming server interceptor that validates incoming messages.
//
// The stage at which invalid messages will be rejected with `InvalidArgument` varies based on the
// type of the RPC. For `ServerStream` (1:m) requests, it will happen before reaching any userspace
// handlers. For `ClientStream` (n:1) or `BidiStream` (n:m) RPCs, the messages will be rejected on
// calls to `stream.Recv()`.
func StreamServerInterceptor() grpc.StreamServerInterceptor {
return func(srv interface{}, stream grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
wrapper := &recvWrapper{stream}
return handler(srv, wrapper)
}
}
type recvWrapper struct {
grpc.ServerStream
}
func (s *recvWrapper) RecvMsg(m interface{}) error {
if err := s.ServerStream.RecvMsg(m); err != nil {
return err
}
if err := validate(m); err != nil {
return err
}
return nil
}
validate()
function actually gets request as interface{}
and you need to use type assertion to cast this request to type you needed as v := req.(type)
.
For example, I typed request to FileForm
and was able to check it's content:
func logFileSize(req interface{}) error {
m := req.(*pdfcompose.FileForm)
println("SizeOfUpfile1: " + strconv.Itoa(int(binary.Size(m.Upfile1))))
if m.Upfile2 != nil {
println("SizeOfUpfile2: " + strconv.Itoa(int(binary.Size(m.Upfile3))))
}
if m.Upfile3 != nil {
println("SizeOfUpfile2: " + strconv.Itoa(int(binary.Size(m.Upfile3))))
}
return nil
}
func (s *recvWrapper) RecvMsg(m interface{}) error {
if err := s.ServerStream.RecvMsg(m); err != nil {
return err
}
//z := m.(pdfcompose.FileForm)
if err := logFileSize(m); err != nil {
return err
}
return nil
}
func StreamServerInterceptor() grpc.StreamServerInterceptor {
return func(srv interface{}, stream grpc.ServerStream, info *grpc.StreamServerInfo, handler grpc.StreamHandler) error {
wrapper := &recvWrapper{stream}
return handler(srv, wrapper)
}
}
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