英文:
How to deserialize a java map
问题
我正在尝试在Go语言中将字节反序列化为对象，这些字节是以以下方式在Java中序列化为字节的：
// myMap是Java中TreeMap<String, Object>的实例
ByteArrayOutputStream a = new ByteArrayOutputStream();
GZIPOutputStream b = new GZIPOutputStream(a);
ObjectOutputStream c = new ObjectOutputStream(b);
c.writeObject(myMap);
c.close();
byte[] bytes = a.toByteArray()
以下是我尝试的步骤：
步骤1 - 使用以下代码解压缩字节（存储在变量result中）：
// att是接收到的字节数组
buf := bytes.NewBuffer(att)
reader, _ := gzip.NewReader(buf)
defer reader.Close()
result, _ := ioutil.ReadAll(reader)
步骤2 - 从解压缩的字节中读取对象 - 但是失败了：
var decodedMap map[string]interface{}
d := gob.NewDecoder(bytes.NewBuffer(result))
err = d.Decode(&decodedMap)
if err != nil {
panic(err)
}
错误信息为"gob: encoded unsigned integer out of range"
但是，当我将（字节数组）result转换为字符串时，在Go语言中我可以看到编码的TreeMap详细信息和内容：
map: �� sr java.util.TreeMap��>-%j� Lt NAMEt JOHNt AGEt 32t LOCODEsr java.lang.Long;���̏#� J valuexr java.lang.Number������ xp y
有人可以帮我解决这个问题吗？
英文:
I am trying to de-serialize bytes into an object in Go, which was serialized into bytes in Java, in the following way:
//myMap is an instance of Java TreeMap<String, Object>
ByteArrayOutputStream a = new ByteArrayOutputStream();
GZIPOutputStream b = new GZIPOutputStream(a);
ObjectOutputStream c = new ObjectOutputStream(b);
c.writeObject(myMap);
c.close();
byte[] bytes = a.toByteArray()
Below are the attempts I made
step1 - uncompressed the bytes (in the variable result) using
//att is the byte array received
buf := bytes.NewBuffer(att)
reader, _ := gzip.NewReader(buf)
defer reader.Close()
result , _ := ioutil.ReadAll(reader)
step2 - read object out of uncompressed bytes - but failed
var decodedMap map[string]interface{}
d := gob.NewDecoder(bytes.NewBuffer(*result*))
err = d.Decode(&decodedMap)
if err != nil {
panic(err)
}
error = gob: encoded unsigned integer out of range
But when I convert the (byte array) result to string in Go, I see the encoded treemap details and the contents
map: �� sr java.util.TreeMap��>-%j� Lt NAMEt JOHNt AGEt 32t LOCODEsr java.lang.Long;���̏#� J valuexr java.lang.Number������ xp y
Can someone help me out here?
答案1
得分: 1
你可以（不容易地）在Go中反序列化这些映射，因为序列化数据包含了Java特定的数据，这些数据用于实例化和初始化原始的Java类（在这种情况下是java.util.TreeMap），而这些数据对于Go应用程序来说是未知的。Java对象序列化和由encoding/gob实现的编码之间没有任何关联；前者是特定于Java的，而后者是特定于Go的。
相反，尝试以一种与语言无关的方式对Java对象进行序列化，例如JSON，然后在Go（或任何其他语言）中进行解码。
英文:
You can't (easily) deserialize those maps in Go, because the serialized data contains Java-specific data, data required to instantiate and initialize the original Java class (java.util.TreeMap in this case), which is obviously unknown to a Go app. Java object serialization and the encoding implemented by encoding/gob have nothing to do with each other; the former is specific to Java and the latter is specific to Go.
Instead try to serialize the Java object in a language-neutral way, e.g. to JSON, which you can decode in Go (or in any other language).
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