英文:
Passing a struct by reference without passing as a *structobject in the function parameters
问题
我需要将一个结构体作为引用传递给一个函数，但是我不能在函数参数中使用指针（*）语法：
func abc(client cleintpassedasrefernce) {
// 在client中进行更改，以便在client的实际内存位置中更新
}
type clienttobepassasref struct {
data int
name string
}
// 调用abc函数
object := clienttobepassasref{}
abc(object)
也许我可以创建另一个结构体，像这样传递对象：
type objectPassedStruct struct {
object *clienttobepassasref
}
然后在函数中稍后访问它？
英文:
I need to pass a struct as a reference to a function; however, I cannot use pointer (*) syntax in my function parameters:
func abc(client cleintpassedasrefernce) {
// make changes in client so that it will be updated in the client actual memory location
}
type clienttobepassasref struct {
data int
name string
}
// calling abc function
object = clienttobepassasref{}
abc(object)
Maybe I can create another struct like type object passed struct
{
object *clienttobepassasref
}
and pass this object and access it later in the function?
答案1
得分: 1
你需要同时更改函数签名和调用函数的方式。此外，你定义了一个名为clienttobepassasref的结构体类型，但是你的函数接受的是一个名为cleintpassedasrefernce的结构体类型，在你的示例中没有定义。我在我的示例中将它们替换为一个名为MyObject的结构体类型。
package main
import (
"fmt"
)
type MyObject struct {
data int
name string
}
// 在这里接受一个指向对象的指针，使用'*'字符
func abc(obj *MyObject) {
// 在客户端中进行更改，以便在客户端的实际内存位置中更新
obj.name = "foo"
}
func main() {
// 调用abc函数
object := MyObject{}
abc(&object)
// 在这里通过引用传递，使用'&'字符
fmt.Println(object.name)
}
英文:
You need to change both the function signature, and the method by which you're calling the function. Also you're defining a struct type called clienttobepassasref but your function is accepting a struct type of cleintpassedasrefernce which is not defined in your example. I replaced these with a struct type in my example called MyObject.
package main
import (
"fmt"
)
type MyObject struct {
data int
name string
}
// accept a pointer to the object here using the '*' character
func abc(obj *MyObject) {
// make changes in client so that it will be updated in the client actual memory location
obj.name = "foo"
}
func main() {
// calling abc function
object := MyObject{}
abc(&object)
// Pass it by reference here with the '&' character
fmt.Println(object.name)
}
答案2
得分: 1
如果您需要更新或更改结构的属性，可以创建一个带有该结构引用的接收器函数（方法），并在该函数（方法）中更新结构的属性。
package main
import "fmt"
type MyObject struct {
data int
name string
}
func (obj *MyObject) abc() {
// 在客户端进行更改，以便在客户端的实际内存位置上进行更新
obj.name = "some name"
obj.data = 10
}
func main() {
// 调用 abc 函数
object := &MyObject{}
object.abc()
fmt.Printf("object = %+v", *object)
//object = {data:10 name:some name}
}
在此处运行代码：链接
参考获取更多知识：
英文:
If you need to update, change struct's properties, then create a function (method) with receiver of that struct reference and update struct's properties in that function (method).
package main
import "fmt"
type MyObject struct {
data int
name string
}
func (obj *MyObject)abc() {
// make changes in client so that it will be updated in the client actual memory location
obj.name = `some name`
obj.data = 10
}
func main() {
// calling abc function
object := &MyObject{}
object.abc()
fmt.Printf("object = %+v", *object)
//object = {data:10 name:some name}
}
run the code here
reference to get some more knowledge
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