英文:
JSON object not unmarshalling, but not throwing errors
问题
我只返回翻译好的部分，以下是翻译的结果：
我只是尝试对这个项目进行一些基本的JSON解组，代码如下：
testJson := `{
"Users": [
{
"id": 1,
"username": "bbrewer"
},
{
"id": 2,
"username": "rsmith"
},
{
"id": 3,
"username": "jmorgan"
},
{
"id": 4,
"username": "dwallis"
}]
}`
我想以这样的方式进行操作，以便我可以使用每个条目的各个组件（例如user.ID或user.UserName）。我已经设置了一个结构体，如下所示：
type UserInfo struct {
ID int `json:"id"`
UserName string `json:"username"`
}
然而，每当我尝试解组时，虽然不会抛出任何错误，但似乎无法正确解析它。当我尝试使用range打印时，没有任何输出，而且似乎我试图将其与之关联的对象为空。我做错了什么？
这是我的完整代码（请注意，我也尝试过不使用UserList类型，而是使用UserInfo结构体类型）：
package main
import "fmt"
import "encoding/json"
type UntypedJson map[string][]interface{}
type UserInfo struct {
ID int `json:"id"`
UserName string `json:"username"`
}
type UserList []UserInfo
func main() {
testJson := `{
"Users": [
{
"id": 1,
"username": "bbrewer"
},
{
"id": 2,
"username": "rsmith"
},
{
"id": 3,
"username": "jmorgan"
},
{
"id": 4,
"username": "dwallis"
}]
}`
var users UserList
json.Unmarshal([]byte(testJson), &users)
for i, v := range users {
fmt.Println("what do")
fmt.Println(i)
fmt.Println(v)
fmt.Println(v.ID)
fmt.Println(v.UserName)
}
}
希望对你有帮助！
英文:
I'm just trying to do some basic JSON unmarshalling for this item:
testJson := `{
"Users": [
{
"id": 1,
"username": "bbrewer"
},
{
"id": 2,
"username": "rsmith"
},
{
"id": 3,
"username": "jmorgan"
},
{
"id": 4,
"username": "dwallis"
}]
}`
I'm trying to do it in such a way that I can work with the individual components for each entry (so like user.ID or user.UserName). I've set up a struct for it like this:
type UserInfo struct {
ID int `json:"id"`
UserName string `json:"username"`
}
However, whenever I try to unmarshal it, while it doesn't throw any errors, it doesn't seem to be parsing it properly. When I try to print using a range, nothing is outputted, and it seems like the object I'm trying to tie it to is just empty. What am I doing wrong?
Here's my full code (note that I've also tried it without the UserList type, with users as the UserInfo struct type):
package main
import "fmt"
//import "net/http"
//import "io/ioutil"
import "encoding/json"
type UntypedJson map[string][]interface{}
type UserInfo struct {
ID int `json:"id"`
UserName string `json:"username"`
}
type UserList []UserInfo
func main() {
testJson := `{
"Users": [
{
"id": 1,
"username": "bbrewer"
},
{
"id": 2,
"username": "rsmith"
},
{
"id": 3,
"username": "jmorgan"
},
{
"id": 4,
"username": "dwallis"
}]
}`
var users UserList
json.Unmarshal([]byte(testJson), &users)
for i, v := range users {
fmt.Println("what do")
fmt.Println(i)
fmt.Println(v)
fmt.Println(v.ID)
fmt.Println(v.UserName)
}
}
答案1
得分: 0
你的代码显然出现了错误，并且你还没有处理它。首先像下面这样处理错误。
err := json.Unmarshal([]byte(testJson), &users)
if err != nil {
// 在这里处理错误。
log.Fatalln(err)
}
回答你的问题，你需要创建一个包含UserInfo数组的类型，如下所示。因为你的JSON字符串已经标注为"Users":[{}]。
type UsersInfo struct {
Users []UserInfo `json:"Users"`
}
然后将你的JSON解析为UsersInfo类型的变量引用。
var users UsersInfo
err := json.Unmarshal([]byte(testJson), &users)
if err != nil {
log.Fatalln(err)
}
你可以在这里运行完整的代码。
英文:
your code obviously getting an error and you haven't handled it. first handle error like below.
err := json.Unmarshal([]byte(testJson), &users)
if err != nil {
//handle error here.
log.Fatalln(err)
}
Answer to your question, you have to create a type including UserInfo array as below. Because your json string has annotated as "Users":[{}]
type UsersInfo struct {
Users []UserInfo `json:"Users"`
}
And unmarshal your json to the UsersInfo type variable reference.
var users UsersInfo
err := json.Unmarshal([]byte(testJson), &users)
if err != nil {
log.Fatalln(err)
}
You can run full code here.
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