golang how to parse time without year, but default to current year

If I have a string such as today's date, in the format "Today is Wed Jun 30", I can parse it with:

time.Parse("Today is Mon, Jan 2")

The year is not included, and so it is defaulted to 0000.
How do I get it to parse the date and default to the current year? I can think of some ugly workarounds, like getting the year and appending it to the string and then parsing it again, but I'm guessing there's a better way.

Add the current year to the result of parsing the string:

t, err := time.Parse("Today is Mon, Jan 2", "Today is Wed, Jun 30")
if err != nil {
	log.Fatal(err)
}
t = t.AddDate(time.Now().Year(), 0, 0)

Run an example on the playground.

You can default to current year instead of 0000 by using strings.Replace() method but it require you doing some string conversion ,I have created a code depicting the same logic :

package main

import (
	"fmt"
	"log"
	"strconv"
	"strings"
	"time"
)

func main() {

	t, err := time.Parse("Today is Mon, Jan 2", "Today is Thu, Jul 1")
	if err != nil {
		log.Fatal(err)
	}
	fmt.Println("t ", t)
	fmt.Println(time.Now())
	year := time.Now().Year()

	fmt.Println(strings.Replace(t.String(), "0000", strconv.Itoa(year), 1))

}

Output:

t  0000-07-01 00:00:00 +0000 UTC
2009-11-10 23:00:00 +0000 UTC m=+0.000000001
2009-07-01 00:00:00 +0000 UTC

Just set it right after you parse it.

t, err := time.Parse("Today is Mon, Jan 2", "Today is Mon, Jan 2")
if err != nil {
    panic(err)
}
t = time.Date(time.Now().Year(), t.Month(), t.Day(), t.Hour(), t.Minute(), t.Second(), t.Nanosecond(), t.Location())