如何裁剪特定的文本？

huangapple
go评论116阅读模式
英文:

How to trim specific text

问题

我有一个文件中的一些文本。文本如下：

  1. #cat tmp 
  2. host = "192.168.2.80"
  3. port = 5432
  4. user = "pnmsuser"
  5. password = "PNMS$$$$$$"
  6. dbname = "pnms"

我想要将文本修整为以下形式：

  1. "192.168.2.80"
  2. 5432
  3. "pnmsuser"
  4. "PNMS$$$$$$"
  5. "pnms"

我尝试了以下修整的方法：

  1. func dbFileTrimming() {
  2.     dat, err := ioutil.ReadFile("tmp")
  3.     check(err)
  5.     for key, line := range strings.Split(strings.TrimRight(string(dat), "\n"), "\n") {
  6.         // println(key, line)
  7.         if key == 3 {
  8.             line := string([]rune(line)[11:])
  9.             fmt.Println(line) 
  10.         } else if key == 4 {
  11.             line := string([]rune(line)[9:])
  12.             fmt.Println(line)
  13.         } else {
  14.             line := string([]rune(line)[7:])
  15.             fmt.Println(line)
  16.         }
  17.     }
  18. }

是否有更简单的方法来实现这个目标？

英文:

I have some text in file.Text like below:

  1. #cat tmp 
  2. host = "192.168.2.80"
  3. port = 5432
  4. user = "pnmsuser"
  5. password = "PNMS$$$$$$"
  6. dbname = "pnms"

Just I want text like below after trimming:

  1. "192.168.2.80"
  2. 5432
  3. "pnmsuser"
  4. "PNMS$$$$$$"
  5. "pnms"

I try to trim like below

  1. func dbFileTrimming() {
  2. 	dat, err := ioutil.ReadFile("tmp")
  3. 	check(err)
  5. 	for key, line := range strings.Split(strings.TrimRight(string(dat), "\n"), "\n") {
  6. 		// println(key, line)
  7. 		if key == 3 {
  8. 			line := string([]rune(line)[11:])
  9. 			fmt.Println(line) 
  10. 		} else if key == 4 {
  11. 			line := string([]rune(line)[9:])
  12. 			fmt.Println(line)
  13. 		} else {
  14. 			line := string([]rune(line)[7:])
  15. 			fmt.Println(line)
  16. 		}
  17. 	}
  18. }

Is there a simple method for this?

答案1

得分: 1

将 = 后面的内容截取出来：

  1. for _, line := range strings.Split(strings.TrimRight(string(dat), "\n"), "\n") {
  2.     line = line[strings.Index(line, " = ")+3:]
  3.     fmt.Println(line)
  4. }
英文:

Chop the line after the =:

  1. for _, line := range strings.Split(strings.TrimRight(string(dat), "\n"), "\n") {
  2.      line = line[strings.Index(line, " = ")+3:]
  3.      fmt.Println(line)
  4. }

答案2

得分: 1

这看起来像是一个INI文件，或者类似的文件，可以使用像go-ini这样的库来处理。

另外，你可以尝试使用Strings.split()函数，并将结果放入一个map中。下面是一个简单而未经测试的示例代码：

  1. result := map[string]string{}
  2. for _, line := range strings.Split(string(dat), "\n") {
  3.   split := strings.Split(line, "=")
  4.   key := strings.Trim(split[0], " ")
  5.   value := strings.Trim(split[1], " ")
  6.   result[key] = value
  7. }
英文:

This looks like an INI file, or similar enough so that libraries like go-ini could work.

Alternatively, try Strings.split() and putting the result in a map. Quick and dirty / untested:

  2. result := map[string]string
  3. for _, line := range strings.Split(string(dat), "\n") {
  4.   split := strings.Split(line, "=")
  5.   key := strings.Trim(split[0])
  6.   value := strings.Trim(split[0])
  7.   result[key] = value
  8. }

huangapple
  • 本文由 发表于 2021年6月28日 22:42:19
  • 转载请务必保留本文链接：https://go.coder-hub.com/68165372.html
  • go
  • postgresql
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