英文:
Reduce a large struct into a small one?
问题
假设我调用了一个 API，它返回一个结构体切片，每个结构体都有很多方法和字段，但我只想使用返回值中每个元素的一个字段。我该如何做到这一点？
例如，我调用一个 API，它返回一个包含 x 个元素的切片，每个元素有 4 个值和 13 个方法，但我只想要一个值和零个方法（即胎儿结构体的切片）。我该如何将其转换为我自己的结构体？例如：
func GETApi() []fetus {
// doGet() 返回一个 persons 的切片，其结构如下所示
a := doGet() // 这将得到一个包含详细 persons 的切片，但我只想要一个 fetus 的切片
/*
type person struct {
id:
age:
height:
width:
}
func (a *person) GetHeight() int { ... }
func (a *person) GetWidth() int { ... }
func (a *person) GetLaught() int { ... }
// 我想要返回这些的切片 ([]fetus)
type fetus struct {
id:
}
var f fetus
f := a // 我该如何将 persons 的切片压缩成 fetus 的切片
return f
}
你可以使用类型转换来将 []person 转换为 []fetus。在这种情况下，你可以使用一个循环来遍历 a 中的每个元素，并将其转换为 fetus 类型的元素，然后将其添加到一个新的切片中。以下是一个示例代码：
func GETApi() []fetus {
a := doGet()
var f []fetus
for _, p := range a {
f = append(f, fetus{id: p.id})
}
return f
}
这样，你就可以将 []person 转换为 []fetus，并只保留 id 字段。
英文:
Say I make a call to an api, which returns a slice of structs, each with a load of methods and fields, but I only want to use one field per each element of the returned values. How can I do this?
For instance, I call out to an API, and it returns a slice of x elements, each which has 4 values and 13method, but I only want 1 value and 0 methods (the slice of fetus structs). How can I marshall this into my own struct? eg:
func GETApi() []fetus {
//doGet() returns a slice of persons, which are described below
a := doGet() // this gets many detailed persons as a slice, but I just want them as a slice of fetus
/*
type person struct {
id:
age:
height:
width:
}
func (a *person) GetHeight() int { ... }
func (a *person) GetWidth() int { ... }
func (a *person) GetLaught() int { ... }
// I want to return a slice of these ([]fetus)
type fetus struct {
id:
}
var f fetus
f := a // how can I condense said slice of persons into a slice of fetus
return f
*/
</details>
# 答案1
**得分**: 2
也许是这样的？
package main
type Person struct {
Id string
Name string
Age string
LotsOfOtherFields string
}
type Fetus struct {
Id string
}
func main() {
persons := []Person{
{Id: "a", Name: "John"},
{Id: "b", Name: "Steve"},
{Id: "c", Name: "Fred"},
}
fetuses := make([]Fetus, len(persons))
for i, p := range persons {
// 创建一个新的胎儿结构体，并从人的结构体中获取ID
fetuses[i] = Fetus{Id: p.Id}
}
}
<details>
<summary>英文:</summary>
Perhaps something like this?
package main
type Person struct {
Id string
Name string
Age string
LotsOfOtherFields string
}
type Fetus struct {
Id string
}
func main() {
persons := []Person{
{Id: "a", Name: "John"},
{Id: "b", Name: "Steve"},
{Id: "c", Name: "Fred"},
}
fetuses := make([]Fetus, len(persons))
for i, p := range persons {
// Create a new fetus struct and pluck the ID from the person struct
fetuses[i] = Fetus{Id: p.Id}
}
}
</details>
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论