英文:
How do I unwrap a wrapped struct in golang?
问题
我一直在搜索，但似乎找不到如何获取Go中包装结构的后端结构的方法。
这是使用情况：我正在使用 traffic 来管理我的 Web 应用程序，它使用自己包装的 http.Request 以及其他几个结构体。声明如下：
type Request struct {
*http.Request
}
我正在尝试集成 go-guardian，我需要将一个 http.Request 发送到以下函数：
Authenticate(r *http.Request) (Info, error)
问题是，我如何获取 traffic.Request 所构建的 *http.Request？
我记得在某个教程中看到过一种方法来做到这一点，但我一直找不到它（问题是我不确定我是否使用了正确的术语来描述包装结构）。
非常感谢您的任何反馈 - 谢谢。
英文:
So I have been searching and can't seem to find how to get the backend struct for a wrapped struct in go.
This is the use case: I am using traffic to manage my web app and it uses it's own wrapped version of the http.Request as well as several others. the declaration looks like this:
type Request struct {
*http.Request
}
I am trying to incorporate go-guardian and I need to send an http.Request to this function:
Authenticate(r *http.Request) (Info, error)
The question is how do I get the *http.Request that the traffic.Request was made out of?
I seem to remember seeing a way to do this in a tutorial somewhere but I haven't been able to find it (the problem is I'm not sure I'm using the right term for a wrapped struct).
Any feedback would be graetly appreciated - thank you.
答案1
得分: 1
嵌入字段可以通过其类型名称进行访问：
type Request struct {
*http.Request
}
对于上述代码：
func f(r *Request) {
// 这将传递嵌入的 *http.Request
g(r.Request)
}
英文:
An embedded field can be accessed using its type name:
type Request struct {
*http.Request
}
For the above:
func f(r *Request) {
// This will pass the embedded *http.Request
g(r.Request)
}
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