英文:
Program executable does not run
问题
如果我运行 go build -o bin/test ./scripts/test.go，我会得到一个可执行文件，但是当我尝试运行它时，我得到以下错误信息：
Failed to execute process './bin/test'. Reason:
exec: Exec format error
The file './bin/test' is marked as an executable but could not be run by the operating system.
scripts/test.go
package scripts
import (
"fmt"
)
func main() {
fmt.Println("hello")
}
英文:
If I run go build -o bin/test ./scripts/test.go I get an executable, but when I try to run it I get
Failed to execute process './bin/test'. Reason:
exec: Exec format error
The file './bin/test' is marked as an executable but could not be run by the operating system.
scripts/test.go
package scripts
import (
"fmt"
)
func main() {
fmt.Println("hello")
}
答案1
得分: 2
应该是package main：
package main
import "fmt"
func main() {
fmt.Println("hello")
}
https://tour.golang.org/welcome
英文:
Should be package main:
package main
import "fmt"
func main() {
fmt.Println("hello")
}
答案2
得分: 1
go build命令的文档中详细介绍了它的工作原理。
总结：
- 构建"main"包将输出一个可执行文件
- 构建非主要包将输出一个对象（并丢弃它）
- 使用
-o进行构建将强制命令不丢弃输出，并将其保存到指定的文件中
所以，你在这里做的基本上是构建一个非主要包，它输出一个对象文件，而不是可执行文件。通常情况下，这会被丢弃，但由于使用了-o选项，你强制将其输出到一个文件中。
要获得一个实际的可执行文件，你只需要将包名更改为main（正如Steven Penny所指出的那样）。
英文:
The documentation for the go build command has the details about how this works.
Summary:
- Building "main" packages will output an executable file
- Building a non-main package will output an object (and discard it)
- Building with
-owill force the command to not discard the output, and save it to the specified file
So basically what you're doing here is building a non-main package, which outputs outputs an object file, not an executable. Normally this is discarded, but due to using the -o option you've forced it to output it to a file.
To get an actual executable, you just need to change the package name to main (as noted by Steven Penny)
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