英文:
Using regular expressions in Go to Identify a common pattern
问题
我正在尝试解析这个字符串 goats=1\r\nalligators=false\r\ntext=works。
contents := "goats=1\r\nalligators=false\r\ntext=works"
compile, err := regexp.Compile("([^#\\s=]+)=([a-zA-Z0-9.]+)")
if err != nil {
return
}
matchString := compile.FindAllStringSubmatch(contents, -1)
我的输出结果是 [[goats=1 goats 1] [alligators=false alligators false] [text=works text works]]。
我在表达式中做错了什么，导致 goats=1 也被认为是有效的？我只想要 [[goats 1]...]。
英文:
I'm trying to parse this string goats=1\r\nalligators=false\r\ntext=works.
contents := "goats=1\r\nalligators=false\r\ntext=works"
compile, err := regexp.Compile("([^#\\s=]+)=([a-zA-Z0-9.]+)")
if err != nil {
return
}
matchString := compile.FindAllStringSubmatch(contents, -1)
my Output looks like [[goats=1 goats 1] [alligators=false alligators false] [text=works text works]]
What I'm I doing wrong in my expression to cause goats=1 to be valid too? I only want [[goats 1]...]
答案1
得分: 1
另一种方法是使用strings包：
package main
import (
"fmt"
"strings"
)
func parse(s string) map[string]string {
m := make(map[string]string)
for _, kv := range strings.Split(s, "\r\n") {
a := strings.Split(kv, "=")
m[a[0]] = a[1]
}
return m
}
func main() {
m := parse("goats=1\r\nalligators=false\r\ntext=works")
fmt.Println(m) // map[alligators:false goats:1 text:works]
}
https://golang.org/pkg/strings
英文:
For another approach, you can use the strings package instead:
package main
import (
"fmt"
"strings"
)
func parse(s string) map[string]string {
m := make(map[string]string)
for _, kv := range strings.Split(s, "\r\n") {
a := strings.Split(kv, "=")
m[a[0]] = a[1]
}
return m
}
func main() {
m := parse("goats=1\r\nalligators=false\r\ntext=works")
fmt.Println(m) // map[alligators:false goats:1 text:works]
}
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